[leetcode]240. Search a 2D Matrix II
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Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted in ascending from left to right.
- Integers in each column are sorted in ascending from top to bottom.
For example,
Consider the following matrix:
[ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23, 26, 30] ]
Given target = 5
, return true
.
Given target = 20
, return false
.
Solution:
matrix[row][col]从右上角开始,向左下角移动。matrix[row][col] > target, 说明col列不存在target, matrix[row][col] < target, 说明row行不存在target
1 bool searchMatrix(int** matrix, int matrixRowSize, int matrixColSize, int target) 2 { 3 int row = 0; 4 int col = matrixColSize - 1; 5 6 while ((row < matrixRowSize) && (col >= 0)) 7 { 8 if (matrix[row][col] == target) 9 return true; 10 else if (matrix[row][col] > target) 11 col--; 12 else 13 row++; 14 } 15 16 return false; 17 }
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