Luogu 1144 最短路计数

Posted 2020-10-05

反思 ：等于号啊等于号，判断要==（=.=）;

#include<cstdio>
#include<algorithm>
#include<cstdlib>
#include<iostream>
#include<vector>
#include<queue>
#include<cstring>
using namespace std;
typedef long long LL;
struct e
{
    int from,to;
};
typedef struct{
    int i,di;
}node;
bool operator < (node a,node b){return a.di>b.di;} 
vector<int>G[1000000];
struct e edge[2000005];
int dis[1000000],num[1000000];
int en=-1;
priority_queue<node>q;
void addedge(int a ,int n)
{
    G[a].push_back(n);
}
int main()
{
    memset(dis,0x7f,sizeof(dis));
    memset(num,0,sizeof(num));
    memset(edge,0,sizeof(edge));
    int n,m,a,b;
    cin>>n>>m;
    for(int i=1;i<=m;i++)
    {
        scanf("%d%d",&a,&b);
        edge[++en]=(struct e){a,b};
        addedge(a,en);
        edge[++en]=(struct e){b,a};
        addedge(b,en);
    }
    
    q.push((node){1,0});
    dis[1]=0;num[1]=1;
    while(!q.empty())
    {
        node x=q.top();
        q.pop();
        if(dis[x.i]!=x.di)continue;
        for(int j=0;j<G[x.i].size();j++)
        {
            if(dis[edge[G[x.i][j]].to]==x.di+1) num[edge[G[x.i][j]].to]=(num[edge[G[x.i][j]].to]+num[x.i])%100003;
            if(dis[edge[G[x.i][j]].to]>x.di+1)
            {
                dis[edge[G[x.i][j]].to]=x.di+1;
                num[edge[G[x.i][j]].to]=num[x.i];
                q.push((node){edge[G[x.i][j]].to,x.di+1});
            }
        }
    }
    for(int j=1;j<=n;j++)
    printf("%d\n",num[j]);
    return 0;
}