HDOJ 1316 How Many Fibs?

Posted 2020-06-29 phlsheji

JAVA大数....

How Many Fibs?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3906    Accepted Submission(s): 1545

Problem Description

Recall the definition of the Fibonacci numbers: 
f1 := 1 
f2 := 2 
fn := fn-1 + fn-2 (n >= 3) 

Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b]. 

 

Input

The input contains several test cases. Each test case consists of two non-negative integer numbers a and b. Input is terminated by a = b = 0. Otherwise, a <= b <= 10^100. The numbers a and b are given with no superfluous leading zeros.

 

Output

For each test case output on a single line the number of Fibonacci numbers fi with a <= fi <= b. 

 

Sample Input

10 100
1234567890 9876543210
0 0

 

Sample Output

5
4

 

Source

University of Ulm Local Contest 2000

 

import java.util.*;
import java.math.*;
import java.io.*;

public class Main
{
	public static void main(String[] args)
	{
		Scanner cin=new Scanner(System.in);
		
		final BigInteger maxlimit=BigInteger.TEN.pow(100);
		BigInteger[] fib=new BigInteger[500];
		
		fib[0]=BigInteger.ONE;
		fib[1]=BigInteger.valueOf(2);
		
		for(int i=2;i<500;i++)
		{
			fib[i]=fib[i-1].add(fib[i-2]);
		}
		
		while(cin.hasNextBigInteger())
		{
			BigInteger a=cin.nextBigInteger();
			BigInteger b=cin.nextBigInteger();
			if(a.compareTo(BigInteger.ZERO)==0&&b.compareTo(BigInteger.ZERO)==0)
				break;
			int ans=0;
			for(int i=0;i<500;i++)
			{
				if(fib[i].compareTo(a)>=0&&fib[i].compareTo(b)<=0)
					ans++;
			}
			System.out.println(ans);
		}
	}	
}