excel2007学习VBA之笔记--计算混合料孔隙比

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1.怎样选择某列有数值的全部?

Dim rng As Range
Set rng=Range([C2],Cells(Rows.Count,"C").End(xlUp))
For Each cell In rng
    ...
Next cell
Sub 遍历某列活动的单元格()
Dim rng As Range
Dim i As Integer
i = 0
Set rng = Range([A1], Cells(Rows.Count, "A").End(xlUp))
For Each cell In rng
   i = i + 1
Next cell
MsgBox i
End Sub

 

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VBA计算混合料孔隙比:

 1 Sub 计算混合料孔隙比()
 2     st_Date = Sheets("表1").Range("I2").Value
 3     Dim e1 As Double, e2 As Double, theta As Double, f As Double
 4     Sheets("sheet1").Range("a1") = "f"
 5     Sheets("sheet1").Range("B1") = "e1"
 6     Sheets("sheet1").Range("C1") = "e2"
 7     Sheets("sheet1").Range("D1") = "theta2low"
 8     Sheets("sheet1").Range("F1") = "f1"
 9     Sheets("sheet1").Range("G1") = "f2"
10     Sheets("sheet1").Range("H1") = "f3"
11     Sheets("sheet1").Range("I1") = "f4"
12     Sheets("sheet1").Range("J1") = "f5"
13     Sheets("sheet1").Range("K1") = "f6"
14     Sheets("sheet1").Range("L1") = "f7"
15     Sheets("sheet1").Range("M1") = "f8"
16     Sheets("sheet1").Range("N1") = "f9"
17     
18     Dim i As Integer, j As Integer
19     给定初始值
20     For i = 2 To 10
21         Sheet1.Cells(i, 1) = "f" & i - 1
22         If i < 10 / 2 + 1 Then
23             Sheet1.Cells(i, 2) = 0.2 * (i - 1) e1
24             Sheet1.Cells(i, 3) = 1 e2
25         Else
26             Sheet1.Cells(i, 2) = 1
27             Sheet1.Cells(i, 3) = 1 - (i - 6) * 0.2
28         End If
29         Sheet1.Cells(i, 4) = (Cells(i, 2) + Cells(i, 2) * Cells(i, 3)) / (Cells(i, 2) + Cells(i, 3) + 2 * Cells(i, 2) * Cells(i, 3))
30     Next i
31     Cells(1, 5) = "theta" 石头所占体积比
32     For i = 2 To 1002
33         Cells(i, 5) = 0 + 0.001 * (i - 2)
34         For j = 1 To 9
35         If Cells(i, 5) < Cells(j + 1, 4) Then
36             Cells(i, j + 5) = Cells(j + 1, 2) * (1 - Cells(i, 5)) / (Cells(i, 5) * Cells(j + 1, 2) + 1)
37         Else
38             Cells(i, j + 5) = Cells(i, 5) * Cells(j + 1, 3) / (1 + Cells(j + 1, 3) * (1 - Cells(i, 5)))
39         End If
40         Next j
41     Next i
42 
43 End Sub

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