扩展欧几里德伪代码

Posted 2020-10-04 1218ghcred

求解二元一次不定方程 mx + ny = gcd(m, n)

 1 int ex_gcd(int m, int n, int &x, int &y)
 2 {
 3     if (n == 0) {
 4         x = 1;
 5         y = 0;
 6         return m;
 7     }
 8     int tmp, g;
 9     g = ex_gcd(n, m % n, x, y);
10     tmp = x;
11     x = y;
12     y = tmp - m / n * y;
13     return g;
14 }