647. Palindromic Substrings 回文子串的数量

Posted Long Long Journey

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了647. Palindromic Substrings 回文子串的数量相关的知识,希望对你有一定的参考价值。

Given a string, your task is to count how many palindromic substrings in this string.

The substrings with different start indexes or end indexes are counted as different substrings even they consist of same characters.

Example 1:

Input: "abc"
Output: 3
Explanation: Three palindromic strings: "a", "b", "c".

Example 2:

Input: "aaa"
Output: 6
Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".

Note:

  1. The input string length won‘t exceed 1000.
求回文子串的数量,每一个子串拥有不同的star index 和不同的end index
  1. class Solution(object):
  2. def countSubstrings(self, s):
  3. """
  4. :type s: str
  5. :rtype: int
  6. """
  7. num = 0
  8. for i in range(0, len(s) + 1):
  9. for j in range(i + 1, len(s) + 1):
  10. sub = s[i:j]
  11. if(sub == sub[::-1]):
  12. num = num + 1
  13. return num






以上是关于647. Palindromic Substrings 回文子串的数量的主要内容,如果未能解决你的问题,请参考以下文章

Leetcode 647: Palindromic Substrings

LeetCode 647. Palindromic Substrings

647. Palindromic Substrings

[LC] 647. Palindromic Substrings

647. Palindromic Substrings

LeetCode 647. 回文子串(Palindromic Substrings)