ACM Bone Collector
Posted 如有一味绝境,非历十方生死
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Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
InputThe first line contain a integer T , the number of cases. The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.OutputOne integer per line representing the maximum of the total value (this number will be less than 2 31).Sample Input
1 5 10 1 2 3 4 5 5 4 3 2 1Sample Output
14
1 #include<bits/stdc++.h> 2 using namespace std; 3 int main() 4 { 5 int dp[1005],n,v,nv[1005],nm[1005],t; 6 while(cin>>t) 7 { 8 while(t--) 9 { 10 memset(dp,0,sizeof(dp)); /*初始化*/ 11 scanf("%d %d",&n,&v); /*读取骨头数量和背包重量*/ 12 for(int i = 0; i < n; i++) /*每一个骨头的价值*/ 13 scanf("%d",&nv[i]); 14 for(int i = 0; i < n; i++) /*每个骨头的重量*/ 15 scanf("%d",&nm[i]); 16 17 for(int i = 0; i < n; i++) 18 for(int j = v; j >= nm[i];j--) /*dp算法*/ 19 dp[j] = max(dp[j],dp[j-nm[i]]+nv[i]); 20 cout<<dp[v]<<endl; 21 } 22 } 23 24 return 0; 25 }
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