HDU 6077 17多校4 Time To Get Up 水题

Posted 2020-10-01 Annetree的博客

Problem Description

Little Q‘s clock is alarming! It‘s time to get up now! However, after reading the time on the clock, Little Q lies down and starts sleeping again. Well, he has 5 alarms, and it‘s just the first one, he can continue sleeping for a while.

Little Q‘s clock uses a standard 7-segment LCD display for all digits, plus two small segments for the ‘‘:‘‘, and shows all times in a 24-hour format. The ‘‘:‘‘ segments are on at all times.



Your job is to help Little Q read the time shown on his clock.

 

 

Input

The first line of the input contains an integer T(1≤T≤1440), denoting the number of test cases.

In each test case, there is an 7×21 ASCII image of the clock screen.

All digit segments are represented by two characters, and each colon segment is represented by one character. The character ‘‘X‘‘ indicates a segment that is on while ‘‘.‘‘ indicates anything else. See the sample input for details.

 

 

Output

For each test case, print a single line containing a string t in the format of HH:MM, where t(00:00≤t≤23:59), denoting the time shown on the clock.

 

 

Sample Input

1

.XX...XX.....XX...XX.

X..X....X......X.X..X

X..X....X.X....X.X..X

......XX.....XX...XX.

X..X.X....X....X.X..X

X..X.X.........X.X..X

.XX...XX.....XX...XX.

 

 

Sample Output

02:38

题意：把字符串翻译成时间。

题解：直接利用他们的区别判断即可。

 1 #include <iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 #include<queue>
 5 #include<map>
 6 #include<vector>
 7 #include<cmath>
 8 #include<cstring>
 9 using namespace std;
10 
11 char time[7+1][21+1];
12 int check(int i)
13 {
14     int j;
15     if(time[6][i]==‘X‘)
16     {
17         if(time[4][i+1]==‘.‘)
18             return 0;
19         else if(time[2][i]==‘.‘)
20             return 2;
21         else if(time[2][i+3]==‘.‘)
22             return 6;
23         else
24             return 8;
25     }
26     else
27     {
28         if(time[2][i]==‘X‘)
29         {
30             if(time[1][i+1]==‘X‘)
31             {
32                 if(time[2][i+3]==‘X‘)
33                     return 9;
34                 else
35                     return 5;
36             }
37             else
38                 return 4;
39         }
40         else
41         {
42             if(time[4][i+1]==‘.‘)
43             {
44                 if(time[1][i+1]==‘X‘)
45                     return 7;
46                 else
47                     return 1;
48             }
49             else
50                 return 3;
51         }
52     }
53 }
54 
55 int main()
56 {
57     int a,b,c,d;
58     int T;
59     scanf("%d",&T);
60     while(T--)
61     {
62         for(int i=1;i<=7;i++)
63             for(int j=1;j<=21;j++)
64                 cin>>time[i][j];
65         a=check(1);
66         b=check(6);
67         c=check(13);
68         d=check(18);
69         printf("%d%d:%d%d\n",a,b,c,d);
70     }
71     return 0;
72 }