Codeforces Round #427 B
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题意:给一个数字,问最少改变多少位可以使得每一位相加大于k
思路:从小的开始改变,每一位变成9,xjb写
AC代码:
#include "iostream" #include "string.h" #include "stack" #include "queue" #include "string" #include "vector" #include "set" #include "map" #include "algorithm" #include "stdio.h" #include "math.h" #pragma comment(linker, "/STACK:102400000,102400000") #define ll long long #define endl ("\n") #define bug(x) cout<<x<<" "<<"UUUUU"<<endl; #define mem(a,x) memset(a,x,sizeof(a)) #define mp(x,y) make_pair(x,y) #define pb(x) push_back(x) #define ft (frist) #define sd (second) #define lrt (rt<<1) #define rrt (rt<<1|1) using namespace std; const long long INF = 1e18+1LL; const int inf = 1e9+1e8; const int N=1e5+100; const ll mod=1e9+7; ///BBBB char s[N]; int k,vis[15]; int main(){ cin>>k>>s+1; int ls=strlen(s+1); ll t=0; for(int i=1; i<=ls; ++i){ t+=s[i]-‘0‘; vis[s[i]-‘0‘]++; } ll c=k-t,ans=0; if(c<=0){ cout<<"0\n"; return 0; } for(int i=0; i<=9; ++i){ if(vis[i]*(9-i) >= c){ ans+=c/(9-i); if(c%(9-i)!=0) ans++; break; } else{ ans+=vis[i]; c-=vis[i]*(9-i); } } cout<<ans<<"\n"; return 0; }
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