hdu 6063 RXD and math

Posted 2020-09-30 早知如此绊人心，何如当初莫相识。

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 typedef long long ll;
 4 const ll mod=1e9+7;
 5 
 6 ll hh(ll x,ll y){
 7     ll s=1;
 8     while(y){
 9         if(y&1) s=s*x%mod;
10         x=x*x%mod;
11         y>>=1;
12     }
13     return s;
14 }
15 int main(){
16     int k=1;
17     ll n,m;
18     while(scanf("%lld%lld",&n,&m)!=EOF){
19         n%=mod;
20         printf("Case #%d: %lld\n",k++,hh(n,m));
21     }
22 }