UVA 11475 Extend to Palindrome KMP

Posted 2020-09-29 Meek

题目链接：https://vjudge.net/problem/UVA-11475

题意：

　　给你一个串S

　　你可以在结尾补充任意数量字母，问最少数量使得新串是回文串

题解：

　　KMP

　　将S串倒置跑KMP

#include<bits/stdc++.h>
using namespace std;
#pragma comment(linker, "/STACK:102400000,102400000")
#define ls i<<1
#define rs ls | 1
#define pii pair<int,int>
#define MP make_pair
typedef long long LL;
typedef unsigned long long ULL;
const long long INF = 1e18+1LL;
const double pi = acos(-1.0);
const int N = 2e5+10, M = 1e3+20,inf = 2e9;

int fail[N];
char a[N],b[N];
int len;
void build_fail() {
    memset(fail,-1,sizeof(fail));
    int j = -1;
    fail[0] = -1;
    for(int i = 1; i < len; ++i) {
        while(j!=-1 && b[i] != b[j+1]) j = fail[j];
        if(b[j+1] == b[i]) j++;
        fail[i] = j;
    }
}
int kmp() {
    int j = -1;
    for(int i = 0; i < len; ++i) {
        while(j!=-1 && a[i]!=b[j+1]) j = fail[j];
        if(b[j+1] == a[i]) j++;
    }
    return j+1;
}
int main() {
    while(scanf("%s",a)!=EOF) {
        len = strlen(a);
        for(int i = 0; i < len; ++i)
            b[len - i - 1] = a[i];
        build_fail();
        cout<<a;
        for(int i = kmp(); i < len; ++i) printf("%c",b[i]);
        printf("\n");
    }
    return 0;
}