Week 1 # F Team Queue

Posted 2020-09-29

题目描述：

F - Team Queue

 

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2645 Accepted Submission(s): 910

 

Problem Description
Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for example. 
In a team queue each element belongs to a team. If an element enters the queue, it first searches the queue from head to tail to check if some of its teammates (elements of the same team) are already in the queue. If yes, it enters the queue right behind them. If not, it enters the queue at the tail and becomes the new last element (bad luck). Dequeuing is done like in normal queues: elements are processed from head to tail in the order they appear in the team queue.

Your task is to write a program that simulates such a team queue.

 

Input
The input will contain one or more test cases. Each test case begins with the number of teams t (1<=t<=1000). Then t team descriptions follow, each one consisting of the number of elements belonging to the team and the elements themselves. Elements are integers in the range 0 - 999999. A team may consist of up to 1000 elements.

Finally, a list of commands follows. There are three different kinds of commands:

ENQUEUE x - enter element x into the team queue 
DEQUEUE - process the first element and remove it from the queue 
STOP - end of test case 
The input will be terminated by a value of 0 for t.

 

Output
For each test case, first print a line saying "Scenario #k", where k is the number of the test case. Then, for each DEQUEUE command, print the element which is dequeued on a single line. Print a blank line after each test case, even after the last one.

 

Sample Input
2
3 101 102 103
3 201 202 203
ENQUEUE 101
ENQUEUE 201
ENQUEUE 102
ENQUEUE 202
ENQUEUE 103
ENQUEUE 203
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
STOP
2
5 259001 259002 259003 259004 259005
6 260001 260002 260003 260004 260005 260006
ENQUEUE 259001
ENQUEUE 260001
ENQUEUE 259002
ENQUEUE 259003
ENQUEUE 259004
ENQUEUE 259005
DEQUEUE
DEQUEUE
ENQUEUE 260002
ENQUEUE 260003
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
STOP
0

Sample Output
Scenario #1
101
102
103
201
202
203

Scenario #2
259001
259002
259003
259004
259005
260001

这个题目用到了map函数和队列的问题。

map: 就是通过（key）来找（value），就是对于每个不同的钥匙都有相对应的值。就是数学中的函数。map函数的头文件#include<map> 定义方式：map<钥匙类型，值的类型>名称  

接下来就是队列，队列不同与栈队列是先进先出更加符合我们的要求。队列的头文件：#include <queue>.队列的定义当式也和栈差不多：queue<类型>名称 队列里面的函数和也是差不多的，除了取首元素，栈用的是top()而队列是front()。

我们这题用map函数来对各团队进行分类，用编号作为钥匙，所在的团队作为value值。而定义一个队列来储存团队的排序，一个数组队列来表示团队队员的排序。剩下的就不细讲了。看看代码吧。

AC代码：

 1 #include <iostream>
 2 #include <map>
 3 #include <queue>
 4 #include <string.h>
 5 const int Max=1010;
 6 using namespace std;
 7 int main()
 8 {
 9     int n,Scenario=1;
10     while(cin>>n&&n)
11     {
12         long long x;
13         map <int ,int > team;
14         for(int i=0;i<n;i++)
15         {
16             int t;
17             cin>>t;
18             for(int k=0;k<t;k++)
19                 {
20                     cin>>x;
21                     team[x]=i;
22                 }
23         }
24         cout<<"Scenario #"<<Scenario<<endl;
25         Scenario++;
26        queue <int> p,q[Max];
27        while(1)
28        {
29            string a;
30            cin>>a;
31            if(a[0]==‘E‘)
32            {
33                int t;
34               cin>>x;
35                t=team[x];
36                if(q[t].empty()) p.push(t);
37                q[t].push(x);
38            }
39            else if(a[0]==‘D‘)
40            {
41                int t=p.front();
42                cout<<q[t].front()<<endl;
43                q[t].pop();
44                if(q[t].empty()) p.pop();
45            }
46            else if(a[0]==‘S‘) break;
47        }
48        cout<<endl;
49     }
50     return 0;
51 }