Coursera Algorithms Programming Assignment 2: Deque and Randomized Queue

Posted 2020-09-28 evasean

作业原文：http://coursera.cs.princeton.edu/algs4/assignments/queues.html

这次作业与第一周作业相比，稍微简单一些。有三个编程练习：双端队列（Deque）设计、随机队列（Randomized Queue）设计，还有一个排列组合类Permutation。

一、双端队列Deque

设计要求：A double-ended queue or deque (pronounced "deck") is a generalization of a stack and a queue that supports adding and removing items from either the front or the back of the data structure.

异常处理要求：Throw a java.lang.IllegalArgumentException if the client attempts to add a null item; throw a java.util.NoSuchElementException if the client attempts to remove an item from an empty deque; throw a java.lang.UnsupportedOperationException if the client calls the remove() method in the iterator; throw a java.util.NoSuchElementException if the client calls the next() method in the iterator and there are no more items to return.

性能要求：Your deque implementation must support each deque operation (including construction) in constant worst-case time. A deque containing n items must use at most 48n + 192 bytes of memory and use space proportional to the number of items currently in the deque. Additionally, your iterator implementation must support each operation (including construction) in constant worst-case time.

分析：

要求可以同时从头尾移除元素，那么该队列内部采用链表更合适，代码如下

  1 import java.util.Iterator;
  2 import java.util.NoSuchElementException;
  3 
  4 public class Deque<Item> implements Iterable<Item> {
  5     private Node first; // 8 bytes
  6     private Node last; // 8 bytes
  7     private int size; // 4 bytes
  8 
  9     private class Node { // 16字节对象开销+8字节内部类额外开销+8+8+8=48 bytes, n个节点就是48n bytes
 10         private Node preNode; // 前一个节点的引用
 11         private Item item;
 12         private Node nextNode; // 后一个节点的引用
 13     }
 14 
 15     private class ListIterator implements Iterator<Item> { 
 16         // 16字节对象开销+8字节内部类额外开销+8=32 bytes
 17         private Node curr = first;
 18 
 19         @Override
 20         public boolean hasNext() {
 21             // TODO Auto-generated method stub
 22             return curr != null;
 23         }
 24 
 25         @Override
 26         public Item next() {
 27             // TODO Auto-generated method stub
 28             if (curr == null)
 29                 throw new NoSuchElementException("there are no more items!");
 30             Item item = curr.item;
 31             curr = curr.nextNode;
 32             return item;
 33         }
 34         //remove不用设计，父类Iterator的remove方法就抛出UnsupportedOperationException("remove");
 35     }
 36 
 37     public Deque() {
 38         // construct an empty deque
 39         size = 0;
 40         first = null;
 41         last = null;
 42     }
 43 
 44     public boolean isEmpty() {
 45         // is the deque empty?
 46         return (size == 0);
 47     }
 48 
 49     public int size() {
 50         // return the number of items on the deque
 51         return size;
 52     }
 53 
 54     public void addFirst(Item item) {
 55         // add the item to the front
 56         valivate(item);
 57         Node newNode = new Node();
 58         newNode.item = item;
 59         if (size == 0) { // 空队列的情况
 60             newNode.preNode = null;
 61             newNode.nextNode = null;
 62             first = newNode;
 63             last = newNode;
 64         } else {
 65             newNode.preNode = null;
 66             newNode.nextNode = first;
 67             first.preNode = newNode;
 68             first = newNode;
 69         }
 70         size++;
 71     }
 72 
 73     public void addLast(Item item) {
 74         // add the item to the end
 75         valivate(item);
 76         Node newNode = new Node();
 77         newNode.item = item;
 78         if (size == 0) { // 空队列的情况
 79             newNode.preNode = null;
 80             newNode.nextNode = null;
 81             first = newNode;
 82             last = newNode;
 83         } else {
 84             last.nextNode = newNode;
 85             newNode.preNode = last;
 86             newNode.nextNode = null;
 87             last = newNode;
 88         }
 89         size++;
 90     }
 91 
 92     public Item removeFirst() {
 93         // remove and return the item from the front
 94         if (size == 0)
 95             throw new NoSuchElementException("the deque is empty!");
 96         Item returnItem = null;
 97         if (size == 1) {
 98             returnItem = first.item;
 99             first = null;
100             last = null;
101         } else {
102             Node oldfirst = first;
103             returnItem = oldfirst.item;
104             first = oldfirst.nextNode;
105             first.preNode = null;
106             oldfirst.nextNode = null;
107             oldfirst.item = null;
108         }
109         size--;
110         return returnItem;
111     }
112 
113     public Item removeLast() {
114         // remove and return the item from the end
115         if (size == 0)
116             throw new NoSuchElementException("the deque is empty!");
117         Item returnItem = null;
118         if (size == 1) {
119             returnItem = first.item;
120             first = null;
121             last = null;
122         } else {
123             Node oldlast = last;
124             returnItem = oldlast.item;
125             last = oldlast.preNode;
126             last.nextNode = null;
127             oldlast.preNode = null;
128             oldlast.item = null;
129         }
130         size--;
131         return returnItem;
132     }
133 
134     public Iterator<Item> iterator() {
135         // return an iterator over items in order from front to end
136         return new ListIterator();
137     }
138 
139     private void valivate(Item item) {
140         if (item == null)
141             throw new IllegalArgumentException("the item is null!");
142     }
143 
144     public static void main(String[] args) {
145         // unit testing (optional)
146         Deque<String> queue = new Deque<String>();
147         System.out.println(queue.size);
148         queue.addFirst("a");
149         queue.addFirst("b");
150         queue.addLast("c");
151         queue.addFirst("d");
152         queue.addLast("e");
153         System.out.println(queue.size);
154         Iterator<String> iter = queue.iterator();
155         while (iter.hasNext()) {
156             System.out.println(iter.next());
157         }
158     }
159 }

二、随机队列Randomized Queue

设计要求：A randomized queue is similar to a stack or queue, except that the item removed is chosen uniformly at random from items in the data structure.

异常处理：The order of two or more iterators to the same randomized queue must be mutually independent; each iterator must maintain its own random order. Throw a java.lang.IllegalArgumentException if the client attempts to add a null item; throw a java.util.NoSuchElementException if the client attempts to sample or dequeue an item from an empty randomized queue; throw a java.lang.UnsupportedOperationException if the client calls the remove() method in the iterator; throw a java.util.NoSuchElementException if the client calls the next() method in the iterator and there are no more items to return.

性能要求： Your randomized queue implementation must support each randomized queue operation (besides creating an iterator) in constant amortized time. That is, any sequence of m randomized queue operations (starting from an empty queue) should take at most cm steps in the worst case, for some constant c. A randomized queue containing n items must use at most 48n + 192 bytes of memory. Additionally, your iterator implementation must support operations next() and hasNext() in constant worst-case time; and construction in linear time; you may (and will need to) use a linear amount of extra memory per iterator.

分析：

该队列每次移除的元素是随机的，性能要求提到迭代器的next方法必须是常数时间，很容易发现链表不容易满足该需求，需要用数组，代码如下：

  1 import java.util.Iterator;
  2 import java.util.NoSuchElementException;
  3 import edu.princeton.cs.algs4.StdRandom;
  4 
  5 public class RandomizedQueue<Item> implements Iterable<Item> {
  6     private Item[] rqArrays;
  7     private int size;
  8 
  9     private class RandomIterator implements Iterator<Item> {
 10         private int rank; // rank 记录便利的次数
 11         private Item[] iterArrays; //两个迭代器必须相互独立，并且拥有自己的随机顺序
 12         
 13         public RandomIterator(){
 14             rank = size;
 15             iterArrays = (Item[]) new Object[rank];
 16             for(int i = 0; i<size; i++){
 17                 iterArrays[i] = rqArrays[i];
 18             }
 19         }
 20         @Override
 21         public boolean hasNext() {
 22             // TODO Auto-generated method stub
 23             return (rank > 0);
 24         }
 25         @Override
 26         public Item next() {
 27             // TODO Auto-generated method stub
 28             if (rank == 0)
 29                 throw new NoSuchElementException("there are no more items!");
 30             int r = StdRandom.uniform(0, rank); // 随机选取一个位置的元素返回
 31             rank--;
 32             Item item = iterArrays[r];
 33             iterArrays[r] = iterArrays[rank];
 34             iterArrays[rank] = item; // 将已经遍历过的元素放置队列末尾，这样下次迭代就不会被选到
 35             return item;
 36         }
 37     }
 38 
 39     public RandomizedQueue() {
 40         // construct an empty randomized queue
 41         rqArrays = (Item[]) new Object[1];
 42         size = 0;
 43     }
 44 
 45     private void valivate(Item item) {
 46         if (item == null)
 47             throw new IllegalArgumentException("the item is null!");
 48     }
 49 
 50     public boolean isEmpty() {
 51         // is the queue empty?
 52         return (size == 0);
 53     }
 54 
 55     public int size() {
 56         // return the number of items on the queue
 57         return size;
 58     }
 59 
 60     private void resize(int cap) {
 61         Item[] temp = (Item[]) new Object[cap];
 62         for (int i = 0; i < size; i++)
 63             temp[i] = rqArrays[i];
 64         rqArrays = temp;
 65     }
 66 
 67     public void enqueue(Item item) {
 68         // add the item
 69         valivate(item);
 70         rqArrays[size++] = item;
 71         if (size == rqArrays.length)
 72             resize(2 * rqArrays.length);
 73     }
 74 
 75     public Item dequeue() {
 76         // remove and return a random item
 77         // 随机选取一个位置，将这个位置的元素与队列末尾的元素交换位置
 78         // dequeue末尾元素时就达到随机remove元素的目的
 79         if (size == 0)
 80             throw new NoSuchElementException("the RandomizeQueue is empty!");
 81         int r = StdRandom.uniform(0, size);
 82         size--;
 83         Item delItem = rqArrays[r];
 84         rqArrays[r] = rqArrays[size];
 85         rqArrays[size] = null;
 86         if (size > 0 && size == rqArrays.length / 4)
 87             resize(rqArrays.length / 2);
 88         return delItem;
 89     }
 90 
 91     public Item sample() {
 92         // return (but do not remove) a random item
 93         if (size == 0)
 94             throw new NoSuchElementException("the RandomizeQueue is empty!");
 95         return rqArrays[StdRandom.uniform(0, size)];
 96     }
 97 
 98     public Iterator<Item> iterator() {
 99         // return an independent iterator over items in random order
100         return new RandomIterator();
101     }
102 
103     public static void main(String[] args) {
104         // unit testing (optional)
105         RandomizedQueue<String> rq = new RandomizedQueue<String>();
106         rq.enqueue("a");
107         rq.enqueue("b");
108         rq.enqueue("c");
109         rq.enqueue("d");
110         rq.enqueue("e");
111         rq.enqueue("f");
112         rq.enqueue("g");
113         rq.dequeue();
114         Iterator<String> iter1 = rq.iterator();
115         Iterator<String> iter2 = rq.iterator();
116         while (iter1.hasNext()) {
117             System.out.print(iter1.next() + ",");
118         }
119         System.out.println();
120         while (iter2.hasNext()) {
121             System.out.print(iter2.next() + ",");
122         }
123         System.out.println();
124 
125     }
126 }

三、 排列组合类Permutation

设计要求：Write a client program Permutation.java that takes a command-line integer k; reads in a sequence of strings from standard input using StdIn.readString(); and prints exactly k of them, uniformly at random. Print each item from the sequence at most once.

性能要求：The running time of Permutation must be linear in the size of the input. You may use only a constant amount of memory plus either one Deque or RandomizedQueue object of maximum size at most n. (For an extra challenge, use only one Deque or RandomizedQueue object of maximum size at most k.)

输出示例：

分析：

显然Permutation要做的事情就是读取一个k，并且从加载的输入文件内容中选取k个String进行展示，故采用RandomizedQueue比较合适。将文件中所有String都放入RandomizedQueue的话其size就是n，如果只放入k个String的话，RandomizedQueue的size就会是k，目前我只实现了size==n的方法，作业提交得分100。size==k的方法需要再斟酌下，若有进展，及时更新。

 1 import edu.princeton.cs.algs4.StdIn;
 2 
 3 public class Permutation {
 4     public static void main(String[] args) {
 5         RandomizedQueue<String> rq = new RandomizedQueue<String>();
 6         int k = Integer.parseInt(args[0]);
 7         while (!StdIn.isEmpty()) {
 8             rq.enqueue(StdIn.readString());
 9             // System.out.println(StdIn.readString());
10         }
11         while (k > 0) {
12             System.out.println(rq.dequeue());
13             k--;
14         }
15     }
16 }