剑指offer57 删除链表中重复的结点

Posted 2020-09-28 去做点事情

错误代码：

class Solution {
public:
    ListNode* deleteDuplication(ListNode* pHead)
    {
        if(pHead == NULL)
            return NULL;
        if(pHead->next == NULL)
            return pHead;
        ListNode* current = NULL;
        if(pHead->val == pHead->next->val){
            current = pHead->next->next;
            while(current->val == pHead->val && current != NULL)
                current = current->next;
            return deleteDuplication(current);
        }
        else{
            current = pHead->next;
            pHead->next = deleteDuplication(current);
        }
        return pHead;
    }
};

正确代码：

class Solution {
public:
    ListNode* deleteDuplication(ListNode* pHead)
    {
        if(pHead == NULL)
            return NULL;
        if(pHead->next==NULL)
            return pHead;
        ListNode* current = NULL;
        if(pHead->val == pHead->next->val){
            current = pHead->next->next;
            while(current != NULL && current->val == pHead->val)
                current = current->next;
               return deleteDuplication(current);
        }
        else{
            current = pHead->next;
            pHead->next = deleteDuplication(current);
            //return pHead;
        }
        return pHead;
    }
};

可以看到不同点只是把current->val == pHead->val和current != NULL换了一下位置

错误的代码报错报的是：段错误:您的程序发生段错误，可能是数组越界，堆栈溢出（比如，递归调用层数太多）等情况引起