计算大于正整数1600000的最小双基回文数

Posted 2020-06-25

def judge(n):
    count=0
    for i in xrange(2,10+1):
        x=‘‘
        tmp=n
        while tmp!=0:
            x+=str(tmp%i)
            tmp/=i
        if x==x[::-1]:
            count+=1
        if count==2:
            return True
    return False

def foo():
    n=1600000
    while True:
        n+=1
        if judge(n):
            print n
            break
    pass

if __name__ == ‘__main__‘:
    foo()
    print ‘ok‘
    pass