三级菜单，可以退出到上一级菜单和全部退出（low版本）

Posted 2020-09-27

menu = {
    ‘北京‘:{
        ‘海淀‘:{
            ‘五道口‘:{
                ‘soho‘:{},
                ‘网易‘:{},
                ‘google‘:{}
            },
            ‘中关村‘:{
                ‘爱奇艺‘:{},
                ‘汽车之家‘:{},
                ‘youku‘:{},
            },
            ‘上地‘:{
                ‘百度‘:{},
            },
        },
        ‘昌平‘:{
            ‘沙河‘:{
                ‘老男孩‘:{},
                ‘北航‘:{},
            },
            ‘天通苑‘:{},
            ‘回龙观‘:{},
        },
        ‘朝阳‘:{},
        ‘东城‘:{},
    },
    ‘上海‘:{
        ‘闵行‘:{
            "人民广场":{
                ‘炸鸡店‘:{}
            }
        },
        ‘闸北‘:{
            ‘火车战‘:{
                ‘携程‘:{}
            }
        },
        ‘浦东‘:{},
    },
    ‘山东‘:{},
}

while True:
    for key in menu:
        print(key)
    choice = input("请输入>>:").strip()
    if len(choice) == 0:continue
    if choice == "b":break
    if choice == "q":exit()
    if choice not in menu:continue

    while True:
        for key2 in menu[choice]:
            print(key2)
        choice2 = input("请输入>>:").strip()
        if len(choice2) == 0: continue
        if choice2 == "b": break
        if choice2 == "q": exit()
        if choice2 not in menu[choice]: continue

        while True:
            for key3 in menu[choice][choice2]:
                print(key3)
            choice3 = input("请输入>>:").strip()
            if len(choice3) == 0: continue
            if choice3 == "b": break
            if choice3 == "q": exit()
            if choice3 not in menu[choice][choice2]: continue

            while True:
                for key4 in menu[choice][choice2][choice3]:
                    print(key4)
                choice4 = input("请输入>>:").strip()
                if len(choice4) == 0: continue
                if choice4 == "b": break
                if choice4 == "q": exit()
                if choice4 not in menu[choice][choice2][choice3]: continue