209. Minimum Size Subarray Sum
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https://leetcode.com/problems/minimum-size-subarray-sum/#/description
Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ? s. If there isn‘t one, return 0 instead.
For example, given the array [2,3,1,2,4,3]
and s = 7
,
the subarray [4,3]
has the minimal length under the problem constraint.
Sol:
https://discuss.leetcode.com/topic/13759/python-3-different-ac-solutions
class Solution(object): def minSubArrayLen(self, s, nums): """ :type s: int :type nums: List[int] :rtype: int """ # two pointers if len(nums) == 0: return 0 sum = 0 i = 0 # fast pointer j j = 0 res = len(nums) + 1 while sum < s: sum += nums[j] j += 1 # to enter the while loop below, sum is greater than s, now let‘s use another pointer i(slow) pointer to find the intervals between i and j. while sum >= s: # if i and j still have elements among them if res > j - i: res = j - i sum -= nums[i] i += 1 if j == len(nums): break # if sum > s at the very beginning, then the program will not enter the first while loop. Thus 0 will be returned. if res > len(nums): return 0 return res
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