PAT-1099(Build A Binary Search Tree)
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题目见这里
(分析) 分四步进行:
1)根据给定的结点情况建二叉树 2)对输入的键值排序(asending) 3)对二叉树中序遍历,同时对应赋key值 4)层次遍历(队列应用)
题目并不困难,但是我误入了trick,错误假定了结点按先序遍历是按顺序编号的(当然是受样例的影响),所以有了下面22分(满分30) 的submit(贴出来是因为这不失为好的巩固二叉树知识的程序)
#include <stdio.h> #include <stdlib.h> //qsort,malloc #define N 105 typedef struct node{ int data; struct node *lChild,*rChild; }BiNode,*BiTree; void CreatBiTree(BiTree *bt){ (*bt) = (BiTree)malloc(sizeof(BiNode)); (*bt)->lChild = (*bt)->rChild = NULL; int left,right; scanf("%d%d",&left,&right); if(left!=-1) CreatBiTree(&((*bt)->lChild)); if(right!=-1) CreatBiTree(&((*bt)->rChild)); } int cmp(const void *a, const void *b){ //asending return *(int *)a - *(int *)b; } void Sort(int *key, int n){ int i; for(i=0;i<n;i++) scanf("%d",&key[i]); qsort((void*)key,n,sizeof(key[0]),cmp); } void LDR(BiTree bt, int key[]){ static int i = 0; if(bt){ LDR(bt->lChild,key); bt->data = key[i++]; LDR(bt->rChild,key); } } void LOT(BiTree bt){ BiTree q[N],bNode; int front,rear,flag; rear = front = flag = 0; q[rear] = bt; while(front<=rear){ bNode = q[front++]; if(!flag){ printf("%d",bNode->data); flag = 1; } else printf(" %d",bNode->data); if(bNode->lChild) q[++rear] = bNode->lChild; if(bNode->rChild) q[++rear] = bNode->rChild; } printf("\n"); } void DestryBiTree(BiTree *bt){ if(*bt){ DestryBiTree(&((*bt)->lChild)); DestryBiTree(&((*bt)->rChild)); free(*bt); } } int main(){ int key[N]; BiTree bt; int n; // freopen("Data.txt","r",stdin); scanf("%d",&n); CreatBiTree(&bt,n); Sort(key,n); LDR(bt,key); //中序遍历 LOT(bt); //层次遍历 DestryBiTree(&bt); return 0; }
当然,既然认识到这个错误,当然是因为找到了反例:
8
7 1
2 3
-1 -1
-1 4
5 6
-1 -1
-1 -1
-1 -1
33 37 34 30 50 43 37 33
从上面的反例中,我们注意到创建链表形式的二叉树是不太可能的,而应采用数组形式,所以有了AC的提交:
#include <stdio.h> #define N 105 typedef struct{ int lChild,rChild; int data; }Node; void CreatBiTree(Node node[], int n){ int i = 0; for(;i<n;i++) scanf("%d%d",&node[i].lChild,&node[i].rChild); } int cmp(const void *a, const void *b){ //asending return *(int *)a - *(int *)b; } void Sort(int *key, int n){ int i; for(i=0;i<n;i++) scanf("%d",&key[i]); qsort((void*)key,n,sizeof(key[0]),cmp); } void LDR(Node *node, int key[], int i){ static int j = 0; if(node[i].lChild!=-1) LDR(node,key,node[i].lChild); node[i].data = key[j++]; if(node[i].rChild!=-1) LDR(node,key,node[i].rChild);//注意不要写误 } void LOT(Node node[]){ Node q[N],qNode; int front,rear; rear = front = 0; q[rear] = node[0]; while(front<=rear){ qNode = q[front++]; if(rear) printf(" "); printf("%d",qNode.data); if(qNode.lChild!=-1) q[++rear] = node[qNode.lChild]; if(qNode.rChild!=-1) q[++rear] = node[qNode.rChild]; } printf("\n"); } int main(){ int key[N]; Node node[N]; int n; // freopen("Data.txt","r",stdin); scanf("%d",&n); CreatBiTree(node,n); Sort(key,n); LDR(node,key,0); //中序遍历 LOT(node); //层次遍历 return 0; }
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