python 根据现有文件树创建文件树

Posted 2020-06-24 X-man

 

# -*- coding: utf-8 -*-
import os, errno

def fileName(path):#获取文件夹
    str = ‘‘
    for i in range(1,len(path.split(‘\\‘))):
        str+=path.split(‘\\‘)[i]+‘\\‘
    return str
    
def mkdir_p(path): #创建目录树
    try:
        os.makedirs(path)
    except OSError as exc: # Python >2.5 (except OSError, exc: for Python <2.5)
        if exc.errno == errno.EEXIST and os.path.isdir(path):
            pass
        else: raise

def fileTraverse(filepath):
#遍历filepath下所有文件，包括子目录
    files = os.listdir(filepath)
    for fi in files:
        fi_d = os.path.join(filepath,fi)            
        if os.path.isdir(fi_d):
            mkdir_p("E:\\"+fileName(fi_d))
            #创建文件夹，文件夹目录树
            fileTraverse(fi_d)#递归遍历               
        else:
            print os.path.join(filepath,fi_d)


root = ‘F:\\目标2‘
root = root.decode(‘utf-8‘)#目录名中有中文，需要decode
fileTraverse(root)