含有对象的List集合实现字母数字混合排序

Posted 2020-09-26 lingluo2017

List<PageData>    varList =  [{BOMCode=10A, mantotal=4}, {BOMCode=10B, mantotal=1}, {BOMCode=11A, mantotal=1}, {BOMCode=11B, mantotal=1}, {BOMCode=12A, mantotal=1}, {BOMCode=1A, mantotal=9}, {BOMCode=2A, mantotal=168}, {BOMCode=2B, mantotal=57}, {BOMCode=3A, mantotal=440}, {BOMCode=3B, mantotal=363}, {BOMCode=4A, mantotal=317}, {BOMCode=4B, mantotal=612}, {BOMCode=5A, mantotal=175}, {BOMCode=5B, mantotal=188}, {BOMCode=6A, mantotal=99}, {BOMCode=6B, mantotal=132}, {BOMCode=7A, mantotal=48}, {BOMCode=7B, mantotal=58}, {BOMCode=8A, mantotal=22}, {BOMCode=8B, mantotal=10}, {BOMCode=9A, mantotal=7}, {BOMCode=9B, mantotal=3}]

现在要对集合对象里面的BOMCode做排序，返回一个排序后的varList：

Collections.sort(varList, new Comparator<PageData>(){                
            /*  
             * int compare(PageData pd1, PageData pd2) 返回一个基本类型的整型，  
             * 返回负数表示：pd1 小于pd2，  
             * 返回0 表示：pd1和pd2相等，  
             * 返回正数表示：pd1大于pd2。  
             */  
            @Override
            public int compare(PageData pd1, PageData pd2) {
                int number1;
                int number2;
                int ascii1 = 0;
                int ascii2 = 0;
                String s1 = pd1.getString("BOMCode");
                String s2 = pd2.getString("BOMCode");
                // 获取每个数字的最后一位，判断是否为大写字母（判断其ASCII码是否在65到90之间）
                if ((int) (s1.toCharArray()[s1.length() - 1]) >= 65
                        && (int) (s1.toCharArray()[s1.length() - 1]) <= 90) {
                    number1 = Integer.parseInt(s1.substring(0,
                            s1.length() - 1));
                    ascii1 = (int) (s1.toCharArray()[s1.length() - 1]);
                } else {
                    number1 = Integer.parseInt(s1);
                }
                if ((int) (s2.toCharArray()[s2.length() - 1]) >= 65
                        && (int) (s2.toCharArray()[s2.length() - 1]) <= 90) {
                    number2 = Integer.parseInt(s2.substring(0,
                            s2.length() - 1));
                    ascii2 = (int) (s2.toCharArray()[s2.length() - 1]);
                } else {
                    number2 = Integer.parseInt(s2);
                }
                // 从小到大排序
                if (number1 > number2) {
                    return 1;
                } else if (number1 == number2) {// 数值相等则判断是否有字母以及字母的顺序
                    // 如果两个都有字母，则判断顺序
                    // 按ASCII码从小到大排列（即从A到Z排列）
                    if (ascii1 < ascii2) {
                        return 1;
                    }
                } 
                return -1;
            }  
        });
        return varList;

最后返回的varList如下：

[{BOMCode=1A, mantotal=9}, {BOMCode=2B, mantotal=57}, {BOMCode=2A, mantotal=168}, {BOMCode=3B, mantotal=363}, {BOMCode=3A, mantotal=440}, {BOMCode=4B, mantotal=612}, {BOMCode=4A, mantotal=317}, {BOMCode=5B, mantotal=188}, {BOMCode=5A, mantotal=175}, {BOMCode=6B, mantotal=132}, {BOMCode=6A, mantotal=99}, {BOMCode=7B, mantotal=58}, {BOMCode=7A, mantotal=48}, {BOMCode=8B, mantotal=10}, {BOMCode=8A, mantotal=22}, {BOMCode=9B, mantotal=3}, {BOMCode=9A, mantotal=7}, {BOMCode=10B, mantotal=1}, {BOMCode=10A, mantotal=4}, {BOMCode=11B, mantotal=1}, {BOMCode=11A, mantotal=1}, {BOMCode=12A, mantotal=1}]