Appium+python 一个简单的登录测试
Posted life.pop(fear)
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Appium+python 一个简单的登录测试相关的知识,希望对你有一定的参考价值。
# coding=utf-8 from appium import webdriver import time import unittest import os import htmlTestRunner class LoginTestLizi(unittest.TestCase): def setUp(self): desired_caps = {} desired_caps[‘platformName‘] = ‘android‘ # 设备系统 desired_caps[‘platformVersion‘] = ‘6.0.1‘ # 设备系统版本 desired_caps[‘deviceName‘] = ‘270f2988‘ # 设备名称 desired_caps[‘appPackage‘] = ‘com.lizi.app‘ # 测试app包名 desired_caps[‘appActivity‘] = ‘.activity.MainActivity‘ # 测试appActivity self.driver = webdriver.Remote(‘http://localhost:4723/wd/hub‘, desired_caps) # 启动app def test_login(self): driver = self.driver # 进入首页后点击‘我的’按钮 driver.find_element_by_name(u‘我的‘).click() time.sleep(2) # 点击登录头像按钮,进行登录,跳转到登录界面 driver.find_element_by_id(‘com.lizi.app:id/user_login_iv‘).click() time.sleep(2) # 输入用户名 driver.find_element_by_id(‘com.lizi.app:id/zhanghao_edittext‘).send_keys(‘18267200735‘) # 输入密码 driver.find_element_by_id(‘com.lizi.app:id/password_edittext‘).send_keys(‘password‘) # 点击确认登录按钮 driver.find_element_by_id(‘com.lizi.app:id/login_button‘).click() time.sleep(3) # 登录成功,页面下滑,不然点击不到设置按钮 driver.swipe(500, 200, 500, 800, 0) time.sleep(2) # 获取登录后的昵称 name = driver.find_element_by_id(‘com.lizi.app:id/login_username_tv‘).text # 添加断言,若昵称不正确,则打印错误信息 try: assert ‘No_matter‘ in name print ‘loginUser is right‘ except AssertionError as e: print ‘loginUser is Error‘ # 点击设置按钮,进入设置页面 driver.find_element_by_id(‘com.lizi.app:id/setting_imageView‘).click() # 点击退出按钮 driver.find_element_by_id(‘com.lizi.app:id/exit_button‘).click() def tearDown(self): self.driver.quit() if __name__ == ‘__main__‘: suite = unittest.TestSuite() suite.addTest(LoginTestLizi(‘test_login‘)) filename = ‘C:\\Temp\\app.html‘ fb = file(filename, ‘wb‘) runner = HTMLTestRunner.HTMLTestRunner(stream=fb, title=‘liziapptestreport‘, description=‘liziapp‘) runner.run(suite) fb.close()
以上是关于Appium+python 一个简单的登录测试的主要内容,如果未能解决你的问题,请参考以下文章
Appium+Python3环境搭建,其实超简单!软件测试教程