Fri Oct 31 18:00:00 UTC+0800 2008转换为yyyy-mm-dd
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这个其实网上有很多例子,都是直接用js在前端做了时间处理,我的处理也一样,想要变成2008-3-31,就用下面的js直接可以处理
function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008 num = num + ""; var date = ""; var month = new Array(); month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6; month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12; var week = new Array(); week["Mon"] = "一"; week["Tue"] = "二"; week["Wed"] = "三"; week["Thu"] = "四"; week["Fri"] = "五"; week["Sat"] = "六"; week["Sun"] = "日"; str = num.split(" "); date = str[5] + "-"; date = date + month[str[1]] + "-" + str[2];//获取到的年月日,要是想加上时分秒,就date = date + month[str[1]] + "-" + str[2]+ " " + str[3]; return date; }
我正好做项目,时间要转换成2008-03,我就直接加了个判断
function spliceZero(param) { if (param < 10) { param = "0" + param; } return param; }
/**
* 下面给个完整的例子
*
**/
function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008
if(num!=""){
num = num + "";
var date = "";
var month = new Array();
month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6;
month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12;
str = num.split(" ");
date = str[5] + "-";
date = date + spliceZero(month[str[1]]);
return date;
}else{
return "";
}
}
function spliceZero(param)
{
if (param < 10) {
param = "0" + param;
}
return param;
}
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