Hihocoder 2月29日

Posted 2020-06-24 fisherinbox

import java.util.Scanner;

public class Main {

    static String[] month={
        "January","February","March","April","May","June","July",
            "August","September","October","November","December"
            };
    public static void main(String[] args){
        Scanner s = new Scanner(System.in);
        int a = s.nextInt();
        //要加循环读入数据，每读入一次调用一次find229
        int sum[] = new int[a];
        String[] date1 = new String[3];
        String[] date2 = new String[3];
        for(int i = 0;i<a;i++){
            for(int j =0;j<3;j++){
                date1[j] = s.next();
            }
            for(int j =0;j<3;j++){
                date2[j] = s.next();
            }
            sum[i] = find229(date1,date2);
        }
        for(int i = 0;i<a;i++){
            System.out.println("Case #"+(i+1)+": "+sum[i]);
        }
        s.close();
    }
    public static int find229(String[] date1,String[] date2){
        int year1 = Integer.valueOf(date1[2]);
        int year2 = Integer.valueOf(date2[2]);
        int day2 = Integer.valueOf(date2[1].split(",")[0]);
        int result = 0;
        for(int i = ((year1-1)/4+1)*4;i<=(year2/4)*4;i = i+4){//保证每个年份能被4整除 
            if(i%400 == 0){
                //从某一个能被400整除的数开始，每400个数里面有96个能被4整除但不能被100整除的数，有一个能被400整除的数，算上尾，不算头
                //比如400~800，则是从401~800有一个能被400整除的数，有96个能被4整除不能被100整除的数
                result++;
                result += (year2/400-i/400)*97;
                //小于ed.year的最大的能被400整除的数
                i = (year2/400)*400;
            }else if(i%100!=0){//不能被400整除时
                result++;
            }
        }
        //考虑起止年份
        if(year1%400==0||(year1%4==0&&year1%100!=0)){
            if(!(month[0].equals(date1[0])||month[1].equals(date1[0]))){
                result--;
            }
        }
        if(year2%400==0||(year2%4==0&&year2%100!=0)){
            if(month[0].equals(date2[0])){                
                result--;
            }else if(month[1].equals(date2[0])&&day2<29){
                result--;
            }
        }
        return result;
    }
}