UVA10370 Above Average

Posted 2020-09-22 llguanli

Above Average

It is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.

The first line of standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, N, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving the final grade (an integer between 0 and 100) of a student in the class. For each case you are to output a line giving the percentage of students whose grade is above average, rounded to 3 decimal places.

Sample Input

5
5 50 50 70 80 100
7 100 95 90 80 70 60 50
3 70 90 80
3 70 90 81
9 100 99 98 97 96 95 94 93 91

Output for Sample Input

40.000%
57.143%
33.333%
66.667%
55.556%

#include <stdio.h>
int arr[1002], id;
double ave;

int main()
{
	int t, n, i, count;
	scanf("%d", &t);
	while(t--){
		scanf("%d", &n);
		ave = 0;
		for(i = 0; i < n; ++i){
			scanf("%d", arr + i);
			ave += arr[i];
		}
		ave /= n;
		count = 0;
		
		for(i = 0; i < n; ++i)
			if(arr[i] > ave) ++count;
		printf("%.3lf%%\n", count * 100.0 / n);
	}
	return 0;
}