hello world for u
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- 题目描述:
-
Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:
h d
e l
l r
lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.
- 输入:
-
There are multiple test cases.Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
- 输出:
-
For each test case, print the input string in the shape of U as specified in the description.
- 样例输入:
-
helloworld! ac.jobdu.com
- 样例输出:
-
h ! e d l l lowor a m c o . c jobdu.
代码:
#include<iostream>
#include<string.h>
using namespace std;
#define max 85
char s[2][max];
int main()
{
int len[2];
int n1, n2, n3;
int i, j;
cin >> s[0];
cin >> s[1];
len[0] = strlen(s[0]);
len[1] = strlen(s[1]);
for (int p = 0; p < 2; p++){
n1 = n3 = (len[p] + 2) / 3;
n2 = len[p] - 2 * n1;
for (i = 0; i < n1 - 1; i++)
{
cout << s[p][i];
for (j = 0; j < n2; j++) cout << " ";
cout << s[p][len[p] - 1 - i] << endl;
}
for (j = i; j < len[p] - i; j++)
cout << s[p][j];
cout << endl;
}
return 0;
}
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