Mysql中使用存储过程返回查询多个表的数据信息

Posted 2020-09-22 黄海的编程知识世界

-- 测试手机号
call P_Base_CheckLogin(‘15584463676‘);

-- 测试登录名
call P_Base_CheckLogin(‘sch000001‘)

-- 测试身份证号
call P_Base_CheckLogin(‘080428402304032042‘)

-- 测试学生手机号
call P_Base_CheckLogin(‘13019212198‘)

drop PROCEDURE IF EXISTS P_Base_CheckLogin;
create procedure  P_Base_CheckLogin(v_loginName      VARCHAR(255))  
label:
BEGIN            
        -- 手机号匹配
        SELECT v_loginName REGEXP "^[1][35678][0-9]{9}$" into @checkResult;            
        if @checkResult=1 then                     
                select p.person_id,p.identity_id,p.person_name  into @person_id,@identity_id,@person_name from  t_base_person p  where p.tel=v_loginName limit 1;
                if @person_id is not null THEN
                    select l.login_name,l.login_password  into @login_name,@login_password from t_sys_loginperson l where [email protected]_id and l.IDENTITY_ID=@identity_id;
                    select @login_name as USER_NAME,@person_id as PERSON_ID,@identity_id as IDENTITY_ID ,@person_name as REAL_NAME,@login_password as PASSWORD;
                    LEAVE label;
                end if;
                
                -- 学生的手机号匹配 
                select p.student_id,6 as identity_id into @person_id,@identity_id  from t_base_student as p where p.STU_TEL=v_loginName limit 1;
                if @person_id is not null THEN
                    select l.login_name,l.login_password  into @login_name,@login_password from t_sys_loginperson l where [email protected]_id and l.IDENTITY_ID=@identity_id;
                    select @login_name as USER_NAME,@person_id as PERSON_ID,@identity_id as IDENTITY_ID ,@person_name as REAL_NAME,@login_password as PASSWORD;
                    LEAVE label;
                end if;
        end if;
    
        -- 身份证号匹配 
        select f_base_check_id_number(v_loginName) into @checkResult;
        if @checkResult=1 then 
                select person_id,identity_id,person_name into @person_id,@identity_id,@person_name from  t_base_person p where p.IDENTITY_NUM=v_loginName limit 1;
                if @person_id is not null THEN
                    select l.login_name,l.login_password  into @login_name,@login_password from t_sys_loginperson l where [email protected]_id and l.IDENTITY_ID=@identity_id;
                    select @login_name as USER_NAME,@person_id as PERSON_ID,@identity_id as IDENTITY_ID ,@person_name as REAL_NAME,@login_password as PASSWORD;
                    LEAVE label;
                end if;
        end if;

    -- 正常登录名查询
        select l.login_name,person_id,identity_id,l.person_name,l.login_password into @login_name,@person_id,@identity_id,@person_name,@login_password from t_sys_loginperson l where l.login_name=v_loginName limit 1;
        if @person_id is not null THEN
            select @login_name as USER_NAME,@person_id as PERSON_ID,@identity_id as IDENTITY_ID ,@person_name as REAL_NAME,@login_password as PASSWORD;
            LEAVE label;
        end if;                
END;

drop function if EXISTS f_base_check_id_number;

CREATE  FUNCTION `f_base_check_id_number`(`idnumber` CHAR(18))
    RETURNS enum(‘1‘,‘0‘)
    LANGUAGE SQL
    NOT DETERMINISTIC
    NO SQL
    SQL SECURITY DEFINER
    COMMENT ‘‘
BEGIN
DECLARE status ENUM(‘1‘,‘0‘) default ‘0‘;
DECLARE verify CHAR(1);
DECLARE sigma INT;
DECLARE remainder INT;

IF length(idnumber) = 18 THEN
    set sigma = cast(substring(idnumber,1,1) as UNSIGNED) * 7
        +cast(substring(idnumber,2,1) as UNSIGNED) * 9
        +cast(substring(idnumber,3,1) as UNSIGNED) * 10
        +cast(substring(idnumber,4,1) as UNSIGNED) * 5
        +cast(substring(idnumber,5,1) as UNSIGNED) * 8
        +cast(substring(idnumber,6,1) as UNSIGNED) * 4
        +cast(substring(idnumber,7,1) as UNSIGNED) * 2
        +cast(substring(idnumber,8,1) as UNSIGNED) * 1
        +cast(substring(idnumber,9,1) as UNSIGNED) * 6
        +cast(substring(idnumber,10,1) as UNSIGNED) * 3
        +cast(substring(idnumber,11,1) as UNSIGNED) * 7
        +cast(substring(idnumber,12,1) as UNSIGNED) * 9
        +cast(substring(idnumber,13,1) as UNSIGNED) * 10
        +cast(substring(idnumber,14,1) as UNSIGNED) * 5
        +cast(substring(idnumber,15,1) as UNSIGNED) * 8
        +cast(substring(idnumber,16,1) as UNSIGNED) * 4
        +cast(substring(idnumber,17,1) as UNSIGNED) * 2;
    set remainder = MOD(sigma,11);
    set verify = (case remainder
        when 0 then ‘1‘ when 1 then ‘0‘ when 2 then ‘X‘ when 3 then ‘9‘
        when 4 then ‘8‘ when 5 then ‘7‘ when 6 then ‘6‘ when 7 then ‘5‘
        when 8 then ‘4‘ when 9 then ‘3‘ when 10 then ‘2‘ else ‘/‘ end
    );

END IF;

IF right(idnumber,1) = verify THEN
    set status = ‘1‘;
END IF;

RETURN status;

END