Lua程序设计之————Lua面向对象2

Posted 2020-09-21 Tinywan

----------------------------------------------------------- Lua面向对象3
local smartMan = {
    name = "Tinywan",
    age = 26,
    money = 800000,
    sayHello = function()
        print("Tinywan say 大家好")
    end
}
local t1 = {}
local mt = {
    __index = smartMan,
    __newindex = function(table, key, value)
        print(key .. "字段不存在不要试图给他赋值")
    end
}
setmetatable(t1, mt)
t1.sayHello = function()
    print("HAHA")
end
t1.sayHello()
--- 输出结果
-- sayHello字段不存在不要试图给他赋值
-- Tinywan say 大家好

 

----------------------------------------------------------- Lua面向对象3
local smartMan = {
    name = "none"
}
local other = {
    name = "大家好，我是无赖的table"
}
local t1 = {}
local mt = {
    __index = smartMan,
    __newindex = other
}
setmetatable(t1, mt)
print("other的名字，赋值前：" .. other.name)
t1.name = "峨眉大侠"
print("other的名字，赋值后：" .. other.name)
print("t1 的名字：" .. t1.name)
--- 输出结果
-- other的名字，赋值前：大家好，我是无赖的table
-- other的名字，赋值后：峨眉大侠
-- t1 的名字：none

 

 

 

 

 

有问题

 

 

local 变量不放在全局函数中去

 

以上不需要 return 返回