69. Sqrt(x)

Posted 2020-06-22 ArgenBarbie

Implement int sqrt(int x).

Compute and return the square root of x.

1.

class Solution {
public:
    int mySqrt(int x) {
        if(x == 0 || x == 1)
            return x;
        int l=1, r=x/2+1, m;
        while(l<=r)
        {
            m = (l+r)>>1;
            long long mul = (long long)m*(long long)m;
            if(mul > x)
                r = m-1;
            else if(mul < x)
                l = m+1;
            else
                return m;
        }
        return r;
    }
};

注意：

long long mul = (long long)m*(long long)m;
这一句中，要先将m转换为long long型，再相乘。

 

2. Newton‘s Method

// http://en.wikipedia.org/wiki/Newton%27s_method
int sqrt_nt(int x) {
    if (x == 0) return 0;
    double last = 0;
    double res = 1;
    while (res != last)
    {
        last = res;
        res = (res + x / res) / 2;
    }
    return int(res);
}