随机数的四则运算2

Posted 2020-06-21 就是潘金莲的野野鬼

  


1 #include<iostream>
  2 #include<fstream>
  3 #include<stdlib.h>
  4 #include<string>
  5 #include<stdio.h>
  6 using namespace std;
  7 #define N 100
  8 
  9 void main()
 10 {
 11     int i,x,y,z,b,fanwei,n1,n2,n3;
 12     int c0,c1,c2,c3,c4,c5,c6,c7,c8,c9;
 13     char t0[20],t1[20],t2[20],t3[20],t4[20],t5[20],t6[20],t7[20],t8[20],t9[20];
 14     string x0,x1,x2,x3,x4,x5,x6,x7,x8,x9;
 15     cout<<"请输入题目的数量："<<endl;
 16     cin>>b;
 17     cout<<"请输入数值范围："<<endl;
 18     cin>>fanwei;
 19     cout<<"请选择输出方式（屏幕/打印）：（1/0）"<<endl;
 20     cin>>z;
 21     if(z==1)
 22     {
 23         for(i=0;i<b;i++)
 24         {
 25             n1=rand()%4;
 26             char a[N]={‘+‘,‘-‘,‘*‘,‘/‘};
 27             x=rand()%10;
 28             y=rand()%3;
 29             int yone=rand()%3;
 30             int ytwo=rand()%3;
 31             int ythree=rand()%3;
 32             int yfour=rand()%3;
 33             int yfive=rand()%3;
 34             int ysix=rand()%3;
 35 
 36             c0=rand()%fanwei;itoa(c0,t0,10);string z0=t0;
 37             c1=rand()%fanwei;itoa(c1,t1,10);string z1=t1;
 38             c2=rand()%fanwei;itoa(c2,t2,10);string z2=t2;
 39             c3=rand()%fanwei;itoa(c3,t3,10);string z3=t3;
 40             c4=rand()%fanwei;itoa(c4,t4,10);string z4=t4;
 41             c5=rand()%fanwei;itoa(c5,t5,10);string z5=t5;
 42             c6=rand()%fanwei;itoa(c6,t6,10);string z6=t6;
 43             c7=rand()%fanwei;itoa(c7,t7,10);string z7=t7;
 44             c8=rand()%fanwei;itoa(c8,t8,10);string z8=t8;
 45             c9=rand()%fanwei;itoa(c9,t9,10);string z9=t9;
 46             x0=z0+a[n1]+z1;
 47             switch(y){
 48             case 0:
 49                 {x1=‘(‘+x0+‘)‘+a[n1]+z2;break;}
 50             case 1:
 51                 {x1=z2+a[n1]+‘(‘+x0+‘)‘;break;}
 52             case 3:
 53                 {x1=x0+a[n1]+z2;break;}
 54             }
 55             switch(yone){
 56             case 0:
 57                 {x2=‘(‘+x1+‘)‘+a[n1]+z3;break;}
 58             case 1:
 59                 {x2=z3+a[n1]+‘(‘+x1+‘)‘;break;}
 60             case 2:
 61                 {x2=z3+a[n1]+x1;break;}
 62             }
 63             switch(ytwo){
 64             case 0:
 65                 {x3=‘(‘+x2+‘)‘+a[n1]+z4;break;}
 66             case 1:
 67                 {x3=z4+a[n1]+‘(‘+x2+‘)‘;break;}
 68             case 2:
 69                 {x3=z4+a[n1]+x2;break;}
 70             }
 71             switch(ythree){
 72             case 0:
 73                 {x4=‘(‘+x3+‘)‘+a[n1]+z5;break;}
 74             case 1:
 75                 {x4=z5+a[n1]+‘(‘+x3+‘)‘;break;}
 76             case 2:
 77                 {x4=z5+a[n1]+x3;break;}
 78             }
 79             switch(yfour){
 80             case 0:
 81                 {x5=‘(‘+x4+‘)‘+a[n1]+z6;break;}
 82             case 1:
 83                 {x5=z6+a[n1]+‘(‘+x4+‘)‘;break;}
 84             case 2:
 85                 {x5=z6+a[n1]+x4;break;}
 86             }
 87             switch(yfive){
 88             case 0:
 89                 {x6=‘(‘+x5+‘)‘+a[n1]+z7;break;}
 90             case 1:
 91                 {x6=z7+a[n1]+‘(‘+x5+‘)‘;break;}
 92             case 2:
 93                 {x6=z7+a[n1]+x5;break;}
 94             }
 95             switch(ysix){
 96             case 0:
 97                 {x7=‘(‘+x6+‘)‘+a[n1]+z8;break;}
 98             case 1:
 99                 {x7=z8+a[n1]+‘(‘+x6+‘)‘;break;}
100             case 2:
101                 {x7=z8+a[n1]+x6;break;}
102             }
103 
104             
105             n2=rand()%3;
106             switch(x){
107             case 0:
108                 {i=i-1;break;}
109             case 1:
110                 {i=i-1;break;}
111             case 2:
112                 {x0=z0+a[n1]+z1;
113                 cout<<x0<<endl;break;}
114             case 3:
115                 {
116                     if(n2==2)
117                     {x1=‘(‘+x0+‘)‘+a[n1]+z2;
118                     cout<<x1<<endl;break;}
119                     if(n2==1)
120                     {x1=z2+a[n1]+‘(‘+x0+‘)‘;
121                     cout<<x1<<endl;break;}
122                     if(n2==0)
123                     {x1=x0+a[n1]+z2;
124                     cout<<x1<<endl;break;}
125                 }
126             case 4:
127                 {
128                     if(n2==2)
129                     {x2=‘(‘+x1+‘)‘+a[n1]+z3;
130                     cout<<x2<<endl;break;}
131                     if(n2==1)
132                     {x2=z3+a[n1]+‘(‘+x1+‘)‘;
133                     cout<<x2<<endl;break;}
134                     if(n2==0)
135                     {x2=z3+a[n1]+x1;
136                     cout<<x2<<endl;break;}
137                 }
138             case 5:
139                 {
140                     if(n2==2)
141                     {x3=‘(‘+x2+‘)‘+a[n1]+z4;
142                     cout<<x3<<endl;break;}
143                     if(n2==1)
144                     {x3=z4+a[n1]+‘(‘+x2+‘)‘;
145                     cout<<x3<<endl;break;}
146                     if(n2==0)
147                     {x3=z4+a[n1]+x2;
148                     cout<<x3<<endl;break;}
149                 }
150             case 6:
151                 {
152                     if(n2==2)
153                     {x4=‘(‘+x3+‘)‘+a[n1]+z5;
154                     cout<<x4<<endl;break;}
155                     if(n2==1)
156                     {x4=z5+a[n1]+‘(‘+x3+‘)‘;
157                     cout<<x4<<endl;break;}
158                     if(n2==0)
159                     {x4=z5+a[n1]+x3;
160                     cout<<x4<<endl;break;}
161                 }
162             case 7:
163                 {
164                     if(n2==2)
165                     {x5=‘(‘+x4+‘)‘+a[n1]+z6; 
166                     cout<<x5<<endl;break;}
167                     else if(n2==1)
168                     {x5=z6+a[n1]+‘(‘+x4+‘)‘;
169                     cout<<x5<<endl;break;}
170                     else if(n2==0)
171                     {x5=x4+a[n1]+z6;
172                     cout<<x5<<endl;break;}
173                 }
174             case 8:
175                 {
176                     if(n2==2)
177                     {x6=‘(‘+x5+‘)‘+a[n1]+z7;
178                     cout<<x6<<endl;break;}
179                     if(n2==1)
180                     {x6=z7+a[n1]+‘(‘+x5+‘)‘;
181                     cout<<x6<<endl;break;}
182                     if(n2==0)
183                     {x6=x5+a[n1]+z7;
184                     cout<<x6<<endl;break;}
185                 }
186             case 9:
187                 {
188                     if(n2==2)
189                     {x7=‘(‘+x6+‘)‘+a[n1]+z8;
190                     cout<<x7<<endl;break;}
191                     if(n2==1)
192                     {x7=z8+a[n1]+‘(‘+x6+‘)‘;
193                     cout<<x7<<endl;break;}
194                     if(n2==0)
195                     {x7=x6+a[n1]+z8;
196                     cout<<x7<<endl;break;}
197                 }
198             }
199         }
200     }
201 }
202 
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