python写个简单的文件上传是有多难，要么那么复杂，要么各种，，，老子来写个简单的

Posted 2020-09-20 liguangsunls

def upload(url,params):
    ‘‘‘
    上传文件到server，不适合大文件
    @params url 你懂的
    @params {"action":"xxx","@file","file_path"}  普通參数 key:value  文件key头部加@
    ‘‘‘
    import os
    import urllib2
    BOUNDARY = "0450de9528f040078csuxianbaozic06"
    data = ""
    for key,value in params.items():
        if "@" in key:
            data += "--%s\r\nContent-Disposition: form-data;"                    " name=\"%s\";filename=\"%s\"\r\nContent-Type: application/octet-stream\r\n\r\n"                   %(BOUNDARY,key.replace("@",""),os.path.basename(value))
            fp = open(value,"rb")
            data += fp.read()
            fp.close()
            data +="\r\n"
        else:
            data += "--%s\r\nContent-Disposition: form-data; name=\"%s\"\r\n\r\n%s\r\n"                    %(BOUNDARY,key,value)

    data += "--%s--"%(BOUNDARY,)

    request = urllib2.Request(url)
    request.add_header("Content-Type","multipart/form-data; boundary="+BOUNDARY)
    return urllib2.urlopen(request,data).read()

upload("http://www.baidu.com",{"@file":"/xxx/xxx.jpg"})