java解析xml

Posted 2020-06-21 angelshelter

<?xml version="1.0" encoding="UTF-8"?>
<mimetype>
    <default>
    <mime-type>text/html</mime-type>
    </default>
    <mime-mapping>
        <extension>zip</extension>
        <mime-type>application/zip</mime-type>
    </mime-mapping>
    <mime-mapping>
        <extension>xml</extension>
        <mime-type>text/xml</mime-type>
    </mime-mapping>
</mimetype>                

1. SAXReader

    public static void main(String[] args) throws FileNotFoundException, UnsupportedEncodingException, DocumentException {
        //流式读取
        File file = new File("mimetype.xml");
        Document doc = new SAXReader().read(file);
        Element mimetype = doc.getRootElement();
        System.out.println("根元素名：" + mimetype.getName());
        Element defaultElement = mimetype.element("default");
        System.out.println("默认元素的mime-type：" + defaultElement.elementText("mime-type"));
        List<Element> mime_mappings = mimetype.elements("mime-mapping");
        System.out.println("元素集合的数据：" + mime_mappings.size());
    }

这是读文件的，好像直接读字符串还不怎么方便。

String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><mimetype></mimetype>";
Reader reader = new StringReader(xml);
Document doc = new SAXReader().read(reader);

以Reader为桥梁来读取String类型的xml  2016-03-12 13:00:27