POJ 题目3237 Tree(Link Cut Tree边权变相反数,求两点最大值)
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Time Limit: 5000MS | Memory Limit: 131072K | |
Total Submissions: 6131 | Accepted: 1682 |
Description
You are given a tree with N nodes. The tree’s nodes are numbered 1 through N and its edges are numbered 1 through N ? 1. Each edge is associated with a weight. Then you are to execute a series of instructions on the tree. The instructions can be one of the following forms:
CHANGE i v |
Change the weight of the ith edge to v |
NEGATE a b |
Negate the weight of every edge on the path from a to b |
QUERY a b |
Find the maximum weight of edges on the path from a to b |
Input
The input contains multiple test cases. The first line of input contains an integer t (t ≤ 20), the number of test cases. Then follow the test cases.
Each test case is preceded by an empty line. The first nonempty line of its contains
N (N ≤ 10,000). The next N ? 1 lines each contains three integers
a, b and c, describing an edge connecting nodes a and
b with weight c. The edges are numbered in the order they appear in the input. Below them are the instructions, each sticking to the specification above. A lines with the word “DONE
” ends the test case.
Output
For each “QUERY
” instruction, output the result on a separate line.
Sample Input
1 3 1 2 1 2 3 2 QUERY 1 2 CHANGE 1 3 QUERY 1 2 DONE
Sample Output
1 3
Source
题目大意:一棵树query查询a到b最大值,change 改动第a条边权值变成b,NEGATE
a到b的全部权值变为相反数
ac代码
Problem: 3237 User: kxh1995 Memory: 3096K Time: 657MS Language: C++ Result: Accepted
#include<stdio.h> #include<string.h> #include<stdio.h> #include<string.h> #include<queue> #include<iostream> #define INF 0x7fffffff #define max(a,b) (a>b?a:b) #define min(a,b) (a>b?b:a) using namespace std; int vis[100500]; struct LCT { int bef[100050],pre[100050],next[100050][2],key[100050],val[100050],belong[100010],maxn[100010],minn[100010],neg[100010]; void init() { memset(pre,0,sizeof(pre)); memset(next,0,sizeof(next)); //memset(key,0,sizeof(key)); memset(neg,0,sizeof(neg)); maxn[0]=-INF; minn[0]=INF; } void pushup(int x) { maxn[x]=key[x]; minn[x]=key[x]; if(next[x][0]) { maxn[x]=max(maxn[x],maxn[next[x][0]]); minn[x]=min(minn[x],minn[next[x][0]]); } if(next[x][1]) { maxn[x]=max(maxn[x],maxn[next[x][1]]); minn[x]=min(minn[x],minn[next[x][1]]); } } void Not(int x) { if(x) { neg[x]^=1; swap(minn[x],maxn[x]); key[x]=-key[x]; minn[x]=-minn[x]; maxn[x]=-maxn[x]; } } void pushdown(int x) { if(neg[x]) { Not(next[x][0]); Not(next[x][1]); neg[x]=0; } } void rotate(int x,int kind) { int y,z; y=pre[x]; z=pre[y]; pushdown(y); pushdown(x); next[y][!kind]=next[x][kind]; pre[next[x][kind]]=y; next[z][next[z][1]==y]=x; pre[x]=z; next[x][kind]=y; pre[y]=x; pushup(y); } void splay(int x) { int rt; for(rt=x;pre[rt];rt=pre[rt]); if(x!=rt) { bef[x]=bef[rt]; bef[rt]=0; pushdown(x); while(pre[x]) { if(next[pre[x]][0]==x) { rotate(x,1); } else rotate(x,0); } pushup(x); } } void access(int x) { int fa; for(fa=0;x;x=bef[x]) { splay(x); pushdown(x); pre[next[x][1]]=0; bef[next[x][1]]=x; next[x][1]=fa; pre[fa]=x; bef[fa]=0; fa=x; pushup(x); } } void change(int x,int y) { int t=belong[x-1]; splay(t); key[t]=y; } int negate(int x,int y) { access(y); for(y=0;x;x=bef[x]) { splay(x); if(!bef[x]) { Not(y); Not(next[x][1]); return 1; } pushdown(x); pre[next[x][1]]=0; bef[next[x][1]]=x; next[x][1]=y; pre[y]=x; bef[y]=0; y=x; pushup(x); } return 0; } int query(int x,int y) { access(y); for(y=0;x;x=bef[x]) { splay(x); if(!bef[x]) { return max(maxn[y],maxn[next[x][1]]); } pushdown(x); pre[next[x][1]]=0; bef[next[x][1]]=x; next[x][1]=y; pre[y]=x; bef[y]=0; y=x; pushup(x); } return 0; } }lct; int head[100010],cnt; struct s { int u,v,w,next; }edge[100010<<1]; void add(int u,int v,int w) { edge[cnt].u=u; edge[cnt].v=v; edge[cnt].w=w; edge[cnt].next=head[u]; head[u]=cnt++; } void bfs(int u) { queue<int>q; memset(vis,0,sizeof(vis)); vis[u]=1; q.push(u); while(!q.empty()) { u=q.front(); q.pop(); for(int i=head[u];i!=-1;i=edge[i].next) { int v=edge[i].v; if(!vis[v]) { lct.bef[v]=u; lct.key[v]=edge[i].w; lct.belong[i>>1]=v; vis[v]=1; q.push(v); } } } } int main() { int t; scanf("%d",&t); while(t--) { int n; scanf("%d",&n); memset(head,-1,sizeof(head)); cnt=0; for(int i=1;i<n;i++) { int a,b,c; scanf("%d%d%d",&a,&b,&c); add(a,b,c); add(b,a,c); } lct.init(); bfs(1); char str[10]; while(scanf("%s",str)!=EOF) { if(str[0]==‘D‘) break; int a,b; scanf("%d%d",&a,&b); if(str[0]==‘Q‘) { printf("%d\n",lct.query(a,b)); } else if(str[0]==‘C‘) lct.change(a,b); else lct.negate(a,b); } } }
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