sql server 2008r2的tempdb很大怎么办

Posted 2023-05-01

　　TEMPDB存放显式创建的临时对象,如表,存储过程,表变量和游标,以及所有版本的已更新记录（如果启用了快照隔离）或所用的隐式基于快照隔离的功能.
　　你的数据库用户多,查询量很大.当然TEMPDB会很大咯.如果可以的话,把SQL SERVER的TEMPDB单独放到一个高速磁盘上,TEMPDB的初始大小根据数据库查询和使用量来确定,建议你直接设定为10G.
　　当然,你也要看看那些查询语句,使用了临时表要记得DROP,如果很大的查询临时结果.譬如SQL SERVER的执行计划里有TABLE SPOOL,可以做成临时表,在使用完之后再删除. 参考技术A 你说的是日志文件还是数据文件？大概多大？

???Sql Server???SQL SERVER ????????????

?????????int   with   ??????   serve   span   ??????   inner   --   blog   

??????:???Sql Server???SQL SERVER ????????????

??????SQL SERVER 2005?????????????????????????????????????????????SQL SERVER 2005???????????????CTE?????????????????????CTE?????????????????????

??????CTE??????????????????Common Table Expression ???SQL SERVER 2005????????????????????????????????????

#??????????????????

1???sql

 1 Create table GroupInfo([Id] int,[GroupName] nvarchar(50),[ParentGroupId] int)
 2 
 3 Insert GroupInfo
 4 
 5 select 0,??????????????????,null union all
 6 
 7 select 1,??????????????????,0 union all
 8 select 2,??????????????????,1 union all
 9 select 3,??????????????????,1 union all
10 select 4,????????????????????????,2 union all
11 select 5,????????????????????????,2 union all
12 select 6,????????????????????????,3 union all
13 select 7,????????????????????????,3 union all
14 
15 select 8, ???????????????,0 union all
16 select 9, ?????????????????????,8 union all
17 select 10,????????????????????????,8 union all
18 select 11,???????????????????????????,9 union all
19 select 12,???????????????????????????,9 union all
20 select 13,??????????????????????????????,10 union all
21 select 14,??????????????????????????????,10 

2????????????

 

#????????????Demo

1???????????????????????????????????????????????????,???????????????????????????

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=1
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.Id=G.ParentGroupId
10 )
11 select * from CTE order by Id

 

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=14
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.ParentGroupId=G.Id
10 )
11 select * from CTE order by Id

2?????????????????????

 1 --??????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select Id,GroupName,ParentGroupId,GroupPath=CAST( GroupName as nvarchar(max)) from GroupInfo where Id=1
 7     union all
 8     select G.*,CAST(CTE.GroupPath+???//???+G.GroupName as nvarchar(max)) as GroupPath from CTE 
 9     inner join GroupInfo as G
10     on CTE.Id=G.ParentGroupId
11 )
12 select * from CTE

 3?????????????????????????????????????????????????????????

 1 --??????id????????????????????????????????????sort??????????????????sort??????????????????????????????????????????????????????
 2 WITH    
 3 CTE
 4 AS 
 5 ( 
 6     SELECT * ,CAST(RIGHT(???000??? + CAST([Id] AS VARCHAR), 3) AS VARCHAR(MAX)) AS sort FROM GroupInfo
 7     WHERE ParentGroupId = 0
 8     UNION ALL
 9     SELECT   GroupInfo.* ,CAST(sort + RIGHT(???000??? + CAST(GroupInfo.[Id] AS VARCHAR),3) AS VARCHAR(MAX)) AS sort
10     FROM CTE
11     INNER JOIN GroupInfo ON CTE.Id = GroupInfo.ParentGroupId
12 )
13 SELECT * FROM CTE ORDER BY sort 

 

4?????????????????????????????????????????????????????????

1 --??????????????????
2 WITH CTE AS (
3     SELECT *,1 AS [Level] FROM GroupInfo WHERE ParentGroupId=0
4     UNION ALL
5     SELECT G.*,CTE.Level+1 FROM GroupInfo as G 
6     JOIN CTE ON CTE.Id =G.ParentGroupId
7 )
8 SELECT * FROM CTE