《DSP using MATLAB》示例Example 9.7
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代码:
%% ------------------------------------------------------------------------ %% Output Info about this m-file fprintf(\'\\n***********************************************************\\n\'); fprintf(\' <DSP using MATLAB> Exameple 9.7 \\n\\n\'); time_stamp = datestr(now, 31); [wkd1, wkd2] = weekday(today, \'long\'); fprintf(\' Now is %20s, and it is %7s \\n\\n\', time_stamp, wkd2); %% ------------------------------------------------------------------------ I = 4; L = 5; %n = 0:2048; k1 = 256; k2 = k1+32; m = 0:(k2-k1); %% ----------------------------------------------------------------- %% Plot %% ----------------------------------------------------------------- Hf1 = figure(\'units\', \'inches\', \'position\', [1, 1, 8, 6], ... \'paperunits\', \'inches\', \'paperposition\', [0, 0, 6, 4], ... \'NumberTitle\', \'off\', \'Name\', \'Exameple 9.7\'); set(gcf,\'Color\',\'white\'); TF = 10; % (a) Full singal bandwidth: alpha = 1 I L alpha = 1; h = intfilt(I, L, alpha); fprintf(\'\\n The Length of filter is %d \\n\', length(h) ); [Hr, w, a, LL] = Hr_Type1(h); Hr_min = min(Hr); w_min = find(Hr == Hr_min); H = abs(freqz(h, 1, w)); Hdb = 20*log10(H/max(H)); min_attn = Hdb(w_min); subplot(2, 2, 1); plot(w/pi, Hr, \'g\', \'linewidth\', 1.0); axis([0, 1, -1, 5]); grid on; xlabel(\'frequency in \\pi units\'); ylabel(\'Amplitude\'); title(\'Amplitude Response:alpha = 1 \', \'fontsize\', TF); set(gca, \'xtick\', [0, 1/I, 1]); set(gca, \'ytick\', [0, I]); subplot(2, 2, 3); plot(w/pi, Hdb, \'m\', \'linewidth\', 1.0); axis([0, 1, -50, 10]); grid on; xlabel(\'frequency in \\pi units\', \'fontsize\', 10); ylabel(\'Decibels\'); title(\' Log-mag Response : alpha = 1 \', \'fontsize\', TF); set(gca, \'xtick\', [0, 1/I, 1]); set(gca, \'ytick\', [-50, round(min_attn), 0]); % (b) Partial signal bandwidth: alpha = 0.75 I L alpha = 0.75; h = intfilt(I, L, alpha); fprintf(\'\\n The Length of filter is %d \\n\', length(h) ); [Hr, w, a, LL] = Hr_Type1(h); Hr_min = max(Hr(end/2:end)); w_min = find(Hr == Hr_min); H = abs(freqz(h, 1, w)); Hdb = 20*log10(H/max(H)); min_attn = Hdb(w_min); subplot(2, 2, 2); plot(w/pi, Hr, \'g\', \'linewidth\', 1.0); axis([0, 1, -1, 5]); grid on; xlabel(\'frequency in \\pi units \'); ylabel(\'Amplitude\'); title(\'Amplitude Response : alpha = 0.75 \', \'fontsize\', TF); set(gca, \'xtick\', [0, 1/I, 1]); set(gca, \'ytick\', [ 0, I]); subplot(2, 2, 4); plot(w/pi, Hdb, \'m\', \'linewidth\', 1.0); axis([0, 1, -50, 10]); grid on; xlabel(\'frequency in \\pi units\'); ylabel(\'Decibels\'); title(\'Log-mag Response: alpha = 0.75\', \'fontsize\', TF); set(gca, \'xtick\', [0, 1/I, 1]); set(gca, \'ytick\', [-50, round(min_attn), 0]);
运行结果:
可见,两种α情况下,intfilt函数得到的脉冲响应h长度为2×I×L-1=2×4×5-1=39,即数组h(n)有39个元素。
对于全频带alpha=1的情况,滤波器在通带和阻带都有更多的振荡,最小的阻带衰减是22dB。这是由过渡带很窄造成的。
当alpha=0.75时,滤波器特征是很宽容的,因此它的响应最小阻带衰减34dB。
另外注意到我们没有完全控制其他设计参数。这些细节本节随后会有更详细的讨论。
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