位运算——Hamming Distance

Posted 2020-09-19 ADong

https://leetcode.com/problems/hamming-distance/#/description

输入：两个整数x，y，且0 ≤ x, y < 2³¹。

输出：x，y的二进制表示，不同的有几位。

Example:

Input: x = 1, y = 4

Output: 2

Explanation:
1   (0 0 0 1)
4   (0 1 0 0)
       ↑   ↑

The above arrows point to positions where the corresponding bits are different.

 1 public class Solution {
 2     public int hammingDistance(int x, int y) {
 3         int count = 0;
 4         for(int i=0; i<32; i++) {
 5             if((x & 1) != (y & 1)) {
 6                 count++;
 7                 x = x >> 1;
 8                 y = y >> 1;
 9             } else {
10                 x = x >> 1;
11                 y = y >> 1;
12             }
13         }
14         return count;
15     }
16 }