58. Length of Last Word
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Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
int lengthOfLastWord(string s) { int l = s.length(), last_n = 0, n = 0, i; for(i=0; i<l; i++) { if(s[i]!=‘ ‘) n++; else { if(n) last_n = n; n = 0; } } return n ? n : last_n; }
注意:
字符串最后可能为空格,要用last_n记录之前单词的长度。
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#Leetcode# 58. Length of Last Word