58. Length of Last Word

Posted ArgenBarbie

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了58. Length of Last Word相关的知识,希望对你有一定的参考价值。

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

int lengthOfLastWord(string s) {
    int l = s.length(), last_n = 0, n = 0, i;
    for(i=0; i<l; i++)
    {
        if(s[i]!= )
            n++;
        else
        {
            if(n)
                last_n = n;
            n = 0;
        }
    }
    return n ? n : last_n;
}

 

注意:

字符串最后可能为空格,要用last_n记录之前单词的长度。

以上是关于58. Length of Last Word的主要内容,如果未能解决你的问题,请参考以下文章

58. Length of Last Word

LeetCode 58. Length of Last Word

#Leetcode# 58. Length of Last Word

58. Length of Last Word [easy] (Python)

58. Length of Last Word

58. Length of Last Word