poj 2683 Ohgas' Fortune 利率计算

Posted 2020-09-19 yutingliuyl

水题。

代码：

//poj 2683
//sep9
#include <iostream>
using namespace std;

int main()
{
	int cases;
	scanf("%d",&cases);
	while(cases--){
		int fund,year,op,ans=-1;
		scanf("%d%d%d",&fund,&year,&op);
		while(op--){
			int A,B,flag,charge;
			double rate;
			scanf("%d%lf%d",&flag,&rate,&charge);
			A=fund;
			if(flag==1){
				for(int i=0;i<year;++i){
					B=(int)A*rate;
					A=A+B-charge;
				}
			}else{
				int cumulative=0;
				for(int i=0;i<year;++i){
					B=(int)A*rate;
					A-=charge;
					cumulative+=B;
				}
				A+=cumulative;	
			}
			ans=max(ans,A);
		}
		printf("%d\n",ans);
	}
	return 0;	
}