Lintcode105.Copy List with Random Pointer
Posted Vincent丶
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题目:
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.
Return a deep copy of the list.
题解:
Solution 1 ()
class Solution { public: RandomListNode *copyRandomList(RandomListNode *head) { if (head == nullptr) return nullptr; RandomListNode* dummy = new RandomListNode(-1); RandomListNode* cur = head; RandomListNode* node = dummy; unordered_map<RandomListNode*, RandomListNode*> map; while (cur) { RandomListNode* tmp = new RandomListNode(cur->label); node->next = tmp; map[cur] = node->next; node = node->next; cur = cur->next; } node = dummy->next; cur = head; while (node) { node->random = map[cur->random]; node = node->next; cur = cur->next; } return dummy->next; } };
Solution 2 ()
class Solution { public: RandomListNode *copyRandomList(RandomListNode *head) { if (!head) return head; RandomListNode* cur = head; while (cur) { RandomListNode* node = new RandomListNode(cur->label); node->next = cur->next; cur->next = node; cur = node->next; } cur = head; while (cur) { if (cur->random) { cur->next->random = cur->random->next; } cur = cur->next->next; } cur = head; RandomListNode* first = cur->next; while (cur) { RandomListNode* tmp = cur->next; cur->next = tmp->next; if (tmp->next) { tmp->next = tmp->next->next; } cur = cur->next; } return first; } };
Solution 3 ()
class Solution { public: RandomListNode *copyRandomList(RandomListNode *head) { RandomListNode *newHead, *l1, *l2; if (head == NULL) return NULL; for (l1 = head; l1 != NULL; l1 = l1->next) { l2 = new RandomListNode(l1->label); l2->next = l1->random; l1->random = l2; } newHead = head->random; for (l1 = head; l1 != NULL; l1 = l1->next) { l2 = l1->random; l2->random = l2->next ? l2->next->random : NULL; } for (l1 = head; l1 != NULL; l1 = l1->next) { l2 = l1->random; l1->random = l2->next; l2->next = l1->next ? l1->next->random : NULL; } return newHead; } };
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