step by step to OpenFOAM:step1

Posted 2023-04-26

参考技术A \1.    Install    blueCFD-Core-2017-2-win64-setup.exe

\2.    打开 blueCFD-Core terminal

\3.      cd  /blueCFD/ofuser-of5 

\4.      mkdir run            创建工作目录

\5.    将目录\blueCFD-Core-2017 \OpenFOAM-5.x \tutorials\ incompressible \icoFoam \cavity\cavity

拷贝到run目录下

\6.      cd cavity            切换到cavity工作目录下

\7.      tree                查看文件目录树，这个步骤可省略

\8.      cat system/blockMeshDict    查看网格设置，这个步骤可省略

\9.    blockMesh                生成网格

        这是在cavity/constant目录下回多个文件夹polyMesh里面包含了生成网格的信息

\10.  checkMesh      检查网格，这一步

\11.    icoFoam        调用求解器计算，使用不可压缩格式计算

\12.    paraFoam 打开后处理paraview查看结果

leetcode1413. Minimum Value to Get Positive Step by Step Sum

题目如下：

Given an array of integers nums, you start with an initial positive value startValue.

In each iteration, you calculate the step by step sum of startValue plus elements in nums (from left to right).

Return the minimum positive value of startValue such that the step by step sum is never less than 1. 

Example 1:

Input: nums = [-3,2,-3,4,2]
Output: 5
Explanation: If you choose startValue = 4, in the third iteration your step by step sum is less than 1.
                step by step sum
                startValue = 4 | startValue = 5 | nums
                  (4 -3 ) = 1  | (5 -3 ) = 2    |  -3
                  (1 +2 ) = 3  | (2 +2 ) = 4    |   2
                  (3 -3 ) = 0  | (4 -3 ) = 1    |  -3
                  (0 +4 ) = 4  | (1 +4 ) = 5    |   4
                  (4 +2 ) = 6  | (5 +2 ) = 7    |   2

Example 2:

Input: nums = [1,2]
Output: 1
Explanation: Minimum start value should be positive. 

Example 3:

Input: nums = [1,-2,-3]
Output: 5

Constraints:

• 1 <= nums.length <= 100
• -100 <= nums[i] <= 100

解题思路：从左往右依次累加nums的和，如果遇到和为负数的情况，只要保证 startValue = min(负数和） + 1 即可；如果全为正数，startValue = 1。

代码如下：

class Solution(object):
    def minStartValue(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        min_val = float(‘inf‘)
        amount = 0
        for i in nums:
            amount += i
            min_val = min(min_val,amount)
        if min_val >= 1:return 1
        else:return abs(min_val) + 1