定义一个学生类，需要有姓名，年龄，考试成绩三个成员属性，创建5个对象，属性可以任意值。OC

Posted 2023-04-26

10、 定义一个学生类，需要有姓名，年龄，考试成绩三个成员属性，创建5个对象，属性可以任意值。（Objective-C）
1) 不使用@property，手动编写他们的访问器方法（getter和setter），注意内存管理（手动管理内存）
2) 增加一个便利构造器（快速构造器）
3) 使用NSLog输出学生对象时，输出信息格式为：My Name Is XXX Age Is XXX Score Is XXX
4) 对5个学生对象按照成绩—》年龄—》姓名优先级排序（成绩相同按照年龄排序，成绩年龄相同按照姓名排序（5个学生的属性值自己随便设定，姓名不考虑中文，按26个大小字母排序））

参考技术A

　　Student.h文件

　　#import <Foundation/Foundation.h>

@interface Student : NSObject

    NSString *name;
    int age;
    float score;

-(void)setName:(NSString *)newname;
-(NSString *)name;
-(void)setAge:(int)newage;
-(int)age;
-(void)setScore:(float)newscore;
-(float)score;
-(Student *)initWithName:(NSString *)newname andAge:(int)newage andScore:(float)newscore;
+(Student *)studentWithName:(NSString *)newname andAge:(int)newage andScore:(float)newscore;
-(NSComparisonResult)compareWithScore:(Student *)stu;
-(NSComparisonResult)compareWithAge:(Student *)stu;
-(NSComparisonResult)compareWithName:(Student *)stu;
@end

Student.m文件

　　#import "Student.h"

@implementation Student
-(void)setName:(NSString *)newname
    name=newname;

-(NSString *)name
    return name;

-(void)setAge:(int)newage
    age=newage;

-(int)age
    return age;

-(void)setScore:(float)newscore
    score=newscore;

-(float)score
    return score;

-(Student *)initWithName:(NSString *)newname andAge:(int)newage andScore:(float)newscore
    self=[super init];
    if (self)
        name=newname;
        age=newage;
        score=newscore;
   
    return self;

+(Student *)studentWithName:(NSString *)newname andAge:(int)newage andScore:(float)newscore
    Student *stu=[[Student alloc]initWithName:newname andAge:newage andScore:newscore];
    return stu;

-(NSComparisonResult)compareWithScore:(Student *)stu
    NSComparisonResult result1;
    if (self.score>stu.score)
        return NSOrderedDescending;
   
    else if (self.score<stu.score)
        return NSOrderedAscending;
   
    else
        return NSOrderedSame;
   
    return result1;

-(NSComparisonResult)compareWithAge:(Student *)stu
    NSComparisonResult result2;
    if (self.age>stu.age)
        return NSOrderedDescending;
    else if(self.age<stu.age)
        return NSOrderedAscending;
   
    else
        return NSOrderedSame;
   
    return result2;

-(NSComparisonResult)compareWithName:(Student *)stu
    return [self.name compare:stu.name];

-(NSString *)description
    NSString *str=[NSString stringWithFormat:@"%f,%d,%@",score,age,name];
    return str;


@end

测试代码

　　 Student *stu=[Student new];
        [stu setScore:65.5];
        [stu setAge:21];
        [stu setName:@"zhangsan"];
        Student *stu1=[Student new];
        [stu1 setScore:70.3];
        [stu1 setAge:19];
        [stu1 setName:@"lisi"];
        Student *stu2=[Student new];
        [stu2 setScore:56.5];
        [stu2 setAge:18];
        [stu2 setName:@"wangwu"];
        Student *stu3=[Student new];
        [stu3 setScore:85.6];
        [stu3 setAge:25];
        [stu3 setName:@"mingming"];
        Student *stu4=[Student new];
        [stu4 setScore:95.4];
        [stu4 setAge:20];
        [stu4 setName:@"xionghong"];
        NSArray *stuArr=[NSArray arrayWithObjects:stu,stu1,stu2,stu3,stu4, nil];
        NSArray *sortArr=[stuArr sortedArrayUsingSelector:@selector(compareWithScore:)];
        NSLog(@"按成绩排序后：");
        for (int i=0; i<sortArr.count; i++)
            Student *a=[sortArr objectAtIndex:i];
            NSLog(@"Myname is %@,age is %d,score is %f",a.name,a.age,a.score);
       
        NSArray *sortArr1=[stuArr sortedArrayUsingSelector:@selector(compareWithAge:)];
        NSLog(@"按年龄排序后：");
            for (int i=0; i<sortArr1.count; i++)
                Student *a=[sortArr1 objectAtIndex:i];
                NSLog(@"Myname is %@,age is %d,score is %f",a.name,a.age,a.score);
           
       
        NSArray *sortArr2=[stuArr sortedArrayUsingSelector:@selector(compareWithName:)];
        NSLog(@"按姓名排序后：");
            for (int i=0; i<sortArr2.count; i++)
                Student *a=[sortArr2 objectAtIndex:i];
                NSLog(@"Myname is %@,age is %d,score is %f",a.name,a.age,a.score);
           
       

参考技术B 有答案了嘛...求分享…… 参考技术C 你这是参加培训机构 留的作业吧！！！

java定义一个学生类，其中包含姓名、年龄、成绩的属性，之后由键盘输入学生的内容，并将内容保存在文件

定义一个学生类，其中包含姓名、年龄、成绩的属性，之后由键盘输入学生的内容，并将内容保存在文件中，所有的操作要求全部使用反射机制完成，即不能使用通过关键字new创建学生类对象的操作。
我想要代码啊，简单写写就行，火烧眉毛啊

Class Student
private String stuName;
private short stuAge;
private double stuScore;
//get,set方法...略
//toString()将所有信息返回


Class test
public static void main(String args[]) throws Exception
//根据反射机制获取Student类
Class.forName("Student.class");
//键盘输入可以用System.in
//将输入的值设置到Student 对象中
//由于是纯文本可以用BufferdWriter类写到一个文件中

参考技术A 从页面上获得学生内容，然后通过反射来实例化类，通过流写文件，你研究下Class类，这个问题就简单了，