HDU 1037

Posted 2020-06-08

Keep on Truckin‘

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 11839    Accepted Submission(s): 8102

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don‘t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We‘re not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

 

 

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

 

 

Output

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler). 
The height of the 18-wheeler is 168 inches.

 

 

Sample Input

180 160 170

 

 

Sample Output

CRASH 160

 

 1 #include <iostream>
 2 #include <cstdio>
 3 
 4 using namespace std;
 5 
 6 int main()
 7 {
 8     int a[3],flag;
 9     while(~scanf("%d%d%d",&a[0],&a[1],&a[2])){
10         flag=0;
11         for(int i=0;i<3;i++){
12             if(a[i]<168){
13                 printf("CRASH %d\n",a[i]);flag=1;
14             }
15         }
16         if(flag == 0)
17             printf("NO CRASH\n");
18 
19     }
20     return 0;
21 }