#27 Remove Element

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题目链接:https://leetcode.com/problems/remove-element/


Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.


//遍历元素,假设须要删除。用数组最后一个元素填充当前元素;下一个循环依旧考察当前元素
int removeElement(int* nums, int numsSize, int val) {
    for(int i = 0; i < numsSize; ++i)
        if(val == nums[i])
            nums[i--] = nums[--numsSize]; 
    return numsSize;
}


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