[poj 2104] K-th Number主席树
Posted ciao_sora
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了[poj 2104] K-th Number主席树相关的知识,希望对你有一定的参考价值。
传送门:http://poj.org/problem?id=2104
保存模版。
#include <cstdio> #include <algorithm> #include <cstring> // Sora Sai Gou!!! const int maxn = 100005, maxm = 5005, maxv = 2000005, nil = maxv - 1; int n, m, a[maxn], b[maxn], siz[maxv], ch[maxv][2], root[maxv], cnt; int t1, t2, t3; inline int fndidx(int key) { int left = 1, right = n, mid; while (left < right) { mid = (left + right) >> 1; if (a[mid] < key) { left = mid + 1; } else { right = mid; } } return left; } void ist(int & ima, int p, int key, int ql, int qr) { if (!ima) { ima = ++cnt; } siz[ima] = siz[p] + 1; if (ql == qr) { return; } int mid = (ql + qr) >> 1; if (key <= mid) { ch[ima][1] = ch[p][1]; ist(ch[ima][0], ch[p][0], key, ql, mid); } else { ch[ima][0] = ch[p][0]; ist(ch[ima][1], ch[p][1], key, mid + 1, qr); } } inline int qry (int l, int r, int kth) { --l; int left = 1, right = n, mid, p1 = root[l], p2 = root[r], tem; while (left < right) { tem = siz[ch[p2][0]] - siz[ch[p1][0]]; mid = (left + right) >> 1; if (kth <= tem) { p2 = ch[p2][0]; p1 = ch[p1][0]; right = mid; } else { kth -= tem; p2 = ch[p2][1]; p1 = ch[p1][1]; left = mid + 1; } } return a[left]; } int main(void) { //freopen("in.txt", "r", stdin); scanf("%d%d", &n, &m); for (int i = 1; i <= n; ++i) { scanf("%d", a + i); } memcpy(b, a, sizeof b); std::sort(a + 1, a + n + 1); for (int i = 1; i <= n; ++i) { b[i] = fndidx(b[i]); } for (int i = 1; i <= n; ++i) { ist(root[i], root[i - 1], b[i], 1, n); } for (int i = 0; i < m; ++i) { scanf("%d%d%d", &t1, &t2, &t3); printf("%d\n", qry(t1, t2, t3)); } return 0; }
以上是关于[poj 2104] K-th Number主席树的主要内容,如果未能解决你的问题,请参考以下文章