Leet CodeString to Integer (atoi) ——常考类型题
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Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
字符串的操作。敲代码常常性遇到。string这个类真的很实用哟,题目要求自行实现atoi的功能:
class Solution { public: int atoi(const char *str) { while(‘ ‘ == *str) { str++; } bool isNegative = false; if(‘-‘ == *str) { isNegative = true; str++; } else if(‘+‘ == *str) { str++; } long long ret = 0; while(*str) { if( isdigit(*str) ) { ret = ret * 10 + (*str - ‘0‘); if(isNegative && (-ret <= INT_MIN)) { return INT_MIN; } if(!isNegative && (ret >= INT_MAX)) { return INT_MAX; } } else { break; } str++; } return (isNegative ?-ret : ret); } };
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