实现五种分组加密模式ECB，CBC，CFB，OFB，CTR

Posted 2020-09-10

没什么好说的，简单无脑！

#include<iostream>
using namespace std;

int ECB()
{
int duan[4];
int messageLen = 16; //需要加密数据的长度
int encLen = 4; //加密分段的长度
int key[4] = {1,0,1,0}; // ECB OFB CFB CTR 初始密码 CBC IV
// CTR 计数器从0开始，每组二进制加1，大小 4*sizeof(int)
int initVec[8] = {0,1,1,0,1,0,0,1};
int message[16] = {1,0,0,1,0,0,0,1,1,1,1,1,0,0,0,0}; //明文
int ciphertext[16]; //密文
int a;
a = messageLen/encLen;
int b=0;
int c=0;
for(int i=1;i<=a;i++)
{
for(int j=0;j<4;j++)
{
c=b+j;
duan[j]=message[c];
if(duan[j]==key[j])
{
duan[j]=0;
}
else
{
duan[j]=1;
}
ciphertext[c]=duan[j];
}
b=b+encLen;
}
for(int w=0;w<messageLen;w++)
{
cout<<ciphertext[w];
cout<<" ";
if(w%4==3)
cout<<endl;
}
return 0;
}

int CBC()
{
int duanchu[4];
int duan[4];
int messageLen = 16; //需要加密数据的长度
int encLen = 4; //加密分段的长度
int key[4] = {1,0,1,0}; // ECB OFB CFB CTR 初始密码 CBC IV
// CTR 计数器从0开始，每组二进制加1，大小 4*sizeof(int)
int initVec[8] = {0,1,1,0,1,0,0,1};
int message[16] = {1,0,0,1,0,0,0,1,1,1,1,1,0,0,0,0}; //明文
int ciphertext[16]; //密文
int a;
a = messageLen/encLen;
int b=0;
int c=0;
for(int o=0;o<4;o++)
{
duanchu[o]=message[o];
}
for(int i=1;i<=a;i++)
{
for(int j=0;j<4;j++)
{
c=b+j;
duan[j]=message[c];
if(duan[j]==duanchu[j])
{
duan[j]=0;
}
else
{
duan[j]=1;
}
if(duan[j]==key[j])
{
duan[j]=0;
}
else
{
duan[j]=1;
}
ciphertext[c]=duan[j];
}
b=b+encLen;
}
for(int w=0;w<messageLen;w++)
{
cout<<ciphertext[w];
cout<<" ";
if(w%4==3)
cout<<endl;
}
return 0;
}

int OFB()
{
int xiangliang[4]={1,0,1,0};
int duan[4];
int messageLen = 16; //需要加密数据的长度
int encLen = 4; //加密分段的长度
int key[4] = {1,0,1,0}; // ECB OFB CFB CTR 初始密码 CBC IV
// CTR 计数器从0开始，每组二进制加1，大小 4*sizeof(int)
int initVec[8] = {0,1,1,0,1,0,0,1};
int message[16] = {1,0,0,1,0,0,0,1,1,1,1,1,0,0,0,0}; //明文
int ciphertext[16]; //密文
int a;
a = messageLen/encLen;
int b=0;
int c=0;
for(int i=1;i<=a;i++)
{
for(int j=0;j<4;j++)
{
c=b+j;
duan[j]=message[c];
if(xiangliang[j]==key[j])
{
xiangliang[j]=0;
}
else
{
xiangliang[j]=1;
}
if(duan[j]==xiangliang[j])
{
duan[j]=0;
}
else
{
duan[j]=1;
}
ciphertext[c]=duan[j];
}
b=b+encLen;
}
for(int w=0;w<messageLen;w++)
{
cout<<ciphertext[w];
cout<<" ";
if(w%4==3)
cout<<endl;
}
return 0;
}

int CFB()
{
int xiangli[6];
int xiangliang[6]={1,0,1,0,0,0};
int duan[4];
int messageLen = 16; //需要加密数据的长度
int encLen = 4; //加密分段的长度
int key[4] = {1,0,1,0}; // ECB OFB CFB CTR 初始密码 CBC IV
// CTR 计数器从0开始，每组二进制加1，大小 4*sizeof(int)
int initVec[8] = {0,1,1,0,1,0,0,1};
int message[16] = {1,0,0,1,0,0,0,1,1,1,1,1,0,0,0,0}; //明文
int ciphertext[16]; //密文
int a;
a = messageLen/encLen;
int b=0;
int c=0;
for(int i=1;i<=a;i++)
{
for(int j=0;j<4;j++)
{
c=b+j;
duan[j]=message[c];
if(xiangliang[j]==key[j])
{
xiangli[j]=0;
}
else
{
xiangli[j]=1;
}
if(duan[j]==xiangli[j])
{
duan[j]=0;
}
else
{
duan[j]=1;
}

ciphertext[c]=duan[j];
}
for(int w=0;w<6;w++)
{
if(w<=1)
{
xiangliang[w]=xiangliang[w+4];
}
else
{
xiangliang[w]=duan[w-2];
}
}
b=b+encLen;
}
for(int w=0;w<messageLen;w++)
{
cout<<ciphertext[w];
cout<<" ";
if(w%4==3)
cout<<endl;
}
return 0;
}

int CTR()
{
int shuchuduan[4];
int couter[4]={0};
int duan[4];
int messageLen = 16; //需要加密数据的长度
int encLen = 4; //加密分段的长度
int key[4] = {1,0,1,0}; // ECB OFB CFB CTR 初始密码 CBC IV
// CTR 计数器从0开始，每组二进制加1，大小 4*sizeof(int)
int initVec[8] = {0,1,1,0,1,0,0,1};
int message[16] = {1,0,0,1,0,0,0,1,1,1,1,1,0,0,0,0}; //明文
int ciphertext[16]; //密文
int a;
a = messageLen/encLen;
int b=0;
int c=0;
for(int i=1;i<=a;i++)
{
for(int j=0;j<4;j++)
{
c=b+j;
duan[j]=message[c];
if(couter[j]==key[j])
{
shuchuduan[j]=0;
}
else
{
shuchuduan[j]=1;
}
if(duan[j]==shuchuduan[j])
{
duan[j]=0;
}
else
{
duan[j]=1;
}
ciphertext[c]=duan[j];
}
b=b+encLen;
for(int s=3;s>=0;s--)
{
if(couter[s]==0)
{
couter[s]=1;
if(s<3)
{
for(int r=3;r>s;r--)
{
couter[r]=0;
}
}
break;
}
}
}
for(int w=0;w<messageLen;w++)
{
cout<<ciphertext[w];
cout<<" ";
if(w%4==3)
cout<<endl;
}
return 0;
}

int main()
{
// show init message
cout<<"ECB"<<endl;
ECB();
cout<<"CBC"<<endl;
CBC();
cout<<"CTR"<<endl;
CTR();
cout<<"CFB"<<endl;
CFB();
cout<<"OFB"<<endl;
OFB();
return 0;
}