抄写作业

Posted 2020-09-09

#include<stdio.h>
struct student
{
    int num;
    char name[20];
    float score;
};
int main()
{
    struct student stu[5]={{10101,"lili",78},{10103,"gygy",98.5},{10106,"fttf",86},{10108,"bbhh",73},{10110,"huhu",100}};
    struct student temp;
    int n=5;
    int i,j,k;
    printf("the order is:\n");
    for(i=0;i<n-1;i++)
    {k=i;
    for(j=i+1;j<n;j++)
    if(stu[j].score>stu[k].score)
    k=j;
    temp=stu[k];stu[k]=stu[i];stu[i]=temp;
    }
    for(i=0;i<n;i++)
    printf("%d\n,%s\n,%f\n",stu[i].num,stu[i].name,stu[i].score);
    return 0;
}
复制代码
the order is: 10110 ,huhu ,100.000000 10103 ,gygy ,98.500000 10106 ,fttf ,86.000000 10101 ,lili ,78.000000 10108 ,bbhh ,73.000000

-------------------------------- Process exited after 0.203 seconds with return value 0 请按任意键继续. . .

 

9.5

复制代码
#include<stdio.h>
#include<string.h>
int main()
{struct student
     long num;
     char name[20];
     char sex;
     float score;
};
struct student stu_1={10101,"Li Lin",‘M‘,89.5};
struct student *p;
p=&stu_1;
printf("%d\n,%s\n,%c\n",stu_1.num,,stu_1.name,stu_1.sex,stu_1.score);
printf("%d\n,%s\n,%c\n",stu_1.num,,stu_1.name,stu_1.sex,stu_1.score);
return 0;
}