抄写例题作业1
Posted 王丫
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9.1
#include"stdio.h" int main() { struct Student //声明结构体类型 sttuct Student { long int num; //以下4行为结构体的成员 char name[20]; char sex; char addr[20]; }a={10101,"Li Lin",\'M\',"Beijing Road"};//定义结构体变量a并初始化 printf("NO.:%d\\nname:%s\\nsex:%c\\naddress:%s\\n",a.num,a.name,a.sex,a.addr); return 0; }
NO.:10101 name:Li Lin sex:M address:Beijing Road -------------------------------- Process exited after 0.09505 seconds with return value 0 请按任意键继续. . .
9.2
#include"stdio.h" int main() { struct Student //声明结构体类型 struct Student { int num; char name[20]; float score; }student1,student2; //定义两个结构体变量 student1,student2 scanf("%d%s%f",&student1.num,student1.name,&student1.score); //输入学生1的数据 scanf("%d%s%f",&student2.num,student2.name,&student2.score); //输入学生2的数据 printf("The higher score is:\\n"); if(student1.score>student2.score) printf("%d %s %6.2f\\n",student1.num,student1.name,student1.score); else if(student1.score<student2.score) printf("%d %s %6.2f\\n",student2.num,student2.name,student2.score); else { printf("%d %s %6.2f\\n",student1.num,student1.name,student1.score); printf("%d %s %6.2f\\n",student2.num,student2.name,student2.score); } return 0; }
01 li 66 02 ni 99 The higher score is: 2 ni 99.00 -------------------------------- Process exited after 12.45 seconds with return value 0 请按任意键继续. . .
9.3
#include"string.h" #include"stdio.h" struct Person //声明结构体类型 struct Person { char name[20]; //候选人姓名 int count; //候选人得票数 }leader[3]={"li",0,"yi",0,"zi",0}; //定义结构体数组并初始化 int main() { int i,j; char leader_name[20]; for(i=1;i<=10;i++) { scanf("%s",leader_name); for(j=0;j<3;j++) if(strcmp(leader_name,leader[j].name)==0)leader[j].count++; } printf("\\nResult:\\n"); for(i=0;i<3;i++) printf("%5s:%d\\n",leader[i].name,leader[i].count); return 0; }
li li yi yi yi zi zi yi yi li Result: li:3 yi:5 zi:2 -------------------------------- Process exited after 28.38 seconds with return value 0 请按任意键继续. . .
9.4
#include"stdio.h" struct Student //声明结构体类型 struct Student { int num; char name[20]; float score; }; int main() { struct Student stu[5]={{10101,"zhang",78},{10103,"wang",98.5},{10106,"li",86},{10108,"ling",73.5},{10110,"sun",100}}; struct Student temp; const int n=5; int i,j,k; printf("The order is:\\n"); for(i=0;i<n-1;i++) { k=i; if(stu[j].score>stu[k].score) k=j; temp=stu[k]; stu[k]=stu[i]; stu[i]=temp; } for(i=0;i<n;i++) printf("%6d %8s %6.2f",stu[i].num,stu[i].name,stu[i].score); printf("\\n"); return 0; }
The order is: 10108 ling 73.50 10103 wang 98.50 10106 li 86.00 10101 zhang 78.00 10110 sun 100.00 -------------------------------- Process exited after 0.101 seconds with return value 0 请按任意键继续. . .
9.5
#include"stdio.h" #include"string.h" int main() { struct Student { long num; char name[20]; char sex; float score; }; struct Student stu_1; struct Student *p; p=&stu_1; stu_1.num=10101; strcpy(stu_1.name,"li lin"); stu_1.sex=\'M\'; stu_1.score=89.5; printf("No.:%1d\\nname:%s\\nsex:%c\\nscore:5.1%f\\n",stu_1.num,stu_1.name,stu_1.sex,stu_1.score); printf("\\nNo.:%1d\\nname:%s\\nsex:%c\\nscore:5.1%f\\n",(*p).num,(*p).name,stu_1.sex,(*p).score); return 0; }
No.:10101 name:li lin sex:M score:5.189.500000 No.:10101 name:li lin sex:M score:5.189.500000 -------------------------------- Process exited after 0.17 seconds with return value 0 请按任意键继续. . .
9.6
#include"stdio.h" struct Student { int num; char name[20]; char sex; int age; }; struct Student stu[3]={{10101,"li lin",\'M\',18},{10102,"wang ya",\'M\',19},{10104,"lu fei",\'F\',20}}; int main() { struct Student *p; printf("No. name sex age\\n"); for(p=stu;p<stu+3;p++) printf("%5d %-20s%2c %4d\\n",p->num,p->name,p->sex,p->age); return 0; }
No. name sex age 10101 li lin M 18 10102 wang ya M 19 10104 lu fei F 20 -------------------------------- Process exited after 0.1014 seconds with return value 0 请按任意键继续. . .
9.7
#include <stdio.h> #define N 3 struct Student { int num; char name[20]; float score[3]; float aver; }; int main() { void input(struct Student stu[]); struct Student max(struct Student stu[]); void print(struct Student stu); struct Student stu[N],*p=stu; input(p); print(max(p)); return 0; } void input(struct Student stu[]) { int i; printf("请输入各学生的信息:学号、姓名、三门学科的成绩:\\n"); for(i=0;i<N;i++) { scanf("%d %s %f %f %f",&stu[i].num,&stu[i].name,&stu[i].score[0],&stu[i].score[1],&stu[i].score[2]); stu[i].aver=(stu[i].score[0]+stu[i].score[1]+stu[i].score[2])/3.0; } } struct Student max(struct Student stu[]) { int i,m=0; for(i=0;i<N;i++) if(stu[i].aver>stu[m].aver)m=i; return stu[m]; } void print(struct Student stud) { printf("\\n成绩最高的学生是:\\n"); printf("学号:%d\\n姓名:%s\\n三门课成绩:%5.1f,%5.1f,%5.1f平均成绩:%6.2f\\n",stud.num,stud.name,stud.score[0],stud.score[1],stud.score[2]); }
请输入各学生的信息:学号、姓名、三门学科的成绩: 01 yaya 11 12 13 02 wangya 14 15 16 03 yy 17 18 19 成绩最高的学生是: 学号:3 姓名:yy 三门课成绩: 17.0, 18.0, 19.0平均成绩: 0.00 -------------------------------- Process exited after 53.69 seconds with return value 0 请按任意键继续. . .
总结:自己打了这么多的例题,发现这个结构体的内容差不多是一样的,只要掌握的一种,这类题做起来就很简单。
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