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Posted 2020-09-07

 

被测试代码的地址：http://www.cnblogs.com/leezoey/p/6530136.html

测试流程图：

根据代码的编译方式为：

测试用例设计

测试函数	耳机数量	外壳数量	护膜数量	预期结果	实际结果
Charge	11	11	11	True	True
	-1	11	11	False	False
	11	-1	11	False	False
	11	11	-1	False	False
	Ex	11	11	False	报错
	11	Ex	11	False	报错
	11	11	Ex	False	报错
	11ex	11	11	False	报错
	11	11ex	11	False	报错
	11	11	11ex	False	报错
commission	1	1	1	9.8	9.8
	10	10	10	98.0	98.0
	100	100	100	1820.0	0.0

根据这个所写的Junit测试代码：

@Before
public void setUp() throws Exception {
}

@SuppressWarnings({ "static-access"})
@Test
public void testCharge() {


assertEquals(true,monyCount.charge("11","11","11"));
assertEquals(false,monyCount.charge("-1","11","11"));
assertEquals(false,monyCount.charge("11","-1","11"));
assertEquals(false,monyCount.charge("11","11","-1"));
assertEquals(false,monyCount.charge("11ex","11","11"));
assertEquals(false,monyCount.charge("11","11ex","11"));
assertEquals(false,monyCount.charge("11","11","11ex"));
assertEquals(false,monyCount.charge("ex","11","11"));
assertEquals(false,monyCount.charge("11","ex","11"));
assertEquals(false,monyCount.charge("11","11","ex"));

}

 

@SuppressWarnings("static-access")
@Test
public void testCommission() {

assertEquals(9.8,monyCount.commission("1", "1", "1"),0.01);
assertEquals(98.0,monyCount.commission("10", "10", "10"),0.01);
assertEquals(1820.0,monyCount.commission("100", "100", "100"),0.01);

}

但是测试的结果进行到测试用例

assertEquals(false,monyCount.charge("11ex","11","11"));便报错，原因为这个方法是会因为输入的不合法（即数据为带字母或者符号）而中止报错

更改测试代码为

@Test
public void testCommission() {

assertEquals(9.8,monyCount.commission("1", "1", "1"),0.01);
assertEquals(98.0,monyCount.commission("10", "10", "10"),0.01);
assertEquals(1820.0,monyCount.commission("100", "100", "100"),0.01);

}

发现前两个测试还是可以进行，但是第3个结果与预期不符合

修改建议：

建议添加对字母和符号的判断以及防崩溃的函数

总的数据计算方法有巨大漏洞，估计为方法上的if(money>=1800)这个判断条件变量写错导致total数据在大于1800的时候变为0