第二次作业+105032014033

Posted 2020-09-07

1.测试代码连接：http://www.cnblogs.com/5257yu/p/6601603.html

2.提出的建议：

　　1)该代码没有按照要求将结果作为字符串输出。

　　2)使用 if 时，应当确保判断条件内所有的范围都能涉及到， if 后面应当接else或者else if。

3.修改后代码：

import java.util.Scanner;

public class Yongjin01 {
    public double Input(double number){
        double num = 0;
        Scanner scanner = new Scanner(System.in);
     try{
        if(num<0){
            System.out.println("输入的数量不满足要求！");
            
        }else{
            num = scanner.nextDouble();
            return num;
        }
     }catch(Exception e){System.out.println("输入不合法！");}
        return num;
                
    }
    public double Commission(double headphone,double shell,double protector){
        double commission = 0;  
        double headphonePrice = 80;
        double shellPrice = 10;
        double protectorPrice = 8;
        double headphonesales = headphonePrice*headphone;
        double shellsales = shellPrice*shell;
        double protectorsales = protectorPrice*protector;
        double sales  = headphonesales+shellsales+protectorsales;
        if(sales>1800){
            commission = 0.10*1000;
            commission = commission+0.15*800;
            commission = commission+0.20*(sales-1800);
        }else if(sales>1000){
            commission = 0.10*1000;
            commission = commission+0.15*(sales-1000);
        }
        else 
            commission = 0.10*sales;
        
        return commission;
    }
}

public class ruance2 {
    public static void main(String[] args) {
        while(true){
        Yongjin01 yj = new Yongjin01();
        System.out.println("请分别输入三种手机配件的销售情况：");
        double headphone = yj.Input(0);
        double shell = yj.Input(0);
        double protector = yj.Input(0);
        System.out.println("耳机数量：" + headphone + "\\n手机壳数量：" + shell
                + " \\n手机贴膜数量：" + protector);
        double commission = yj.Commission(headphone, shell, protector);
        System.out.println("销售佣金：" + commission);
    }
}
}

4.心得体会

根据测试者的建议增加了else if判定，解决了输入数较小是出现负数的问题，改进了程序的功能，能够符合题意，符合实际。