ruby reduce方法

Posted 2020-09-05 miaomiaotab

 

Ruby 中一些好用的方法(注意reduce方法)

2016-07-27 17:57 370人阅读 评论(0) 收藏 举报

#####inject

inject是我使用最频繁的方法了，它的强大之处在于可以方便的对嵌套的数组，哈希等混合数据结构进行合并或求和， 可以有效减少代码量。

例如最常见的数组套哈希：

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array = [{a:100}, {b:200}, {c:300}] array.inject(0) { |sum, e| sum += e.values.first } #600 array.inject({}) { |sum, e| sum.merge e } #{:a=>100, :b=>200, :c=>300}

• inject():括号中的是sum的初始值
• sum, e: 和在前，数组元素在后，中间必须以逗号隔开

#####group_by

group_by适用于对于数组和hash的分组. 在stackoverflow,我经常遇到这样的问题：

array根据相同的school_id进行分组

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array = [{"school_id"=>"1", "plan_type"=>"All", "view"=>"true", "create"=>"true", "approve"=>"true", "grant"=>"true", "region_id"=>nil}, {"school_id"=>"1", "plan_type"=>"All", "edit"=>"true", "region_id"=>nil}, {"school_id"=>"2", "plan_type"=>"All", "edit"=>"true", "grant"=>"true", "region_id"=>nil}] array.group_by { |e| e["school_id"] } => {"1"=>[{"school_id"=>"1", "plan_type"=>"All", "view"=>"true", "create"=>"true", "approve"=>"true", "grant"=>"true", "region_id"=>nil}, {"school_id"=>"1", "plan_type"=>"All", "edit"=>"true", "region_id"=>nil}], "2"=>[{"school_id"=>"2", "plan_type"=>"All", "edit"=>"true", "grant"=>"true", "region_id"=>nil}]}

多条件分组：

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array.group_by { |e| [e["school_id"], e["plan_type"]] } #将多个条件放在数组当中 => {["1", "All"]=>[{"school_id"=>"1", "plan_type"=>"All", "view"=>"true", "create"=>"true", "approve"=>"true", "grant"=>"true", "region_id"=>nil}, {"school_id"=>"1", "plan_type"=>"All", "edit"=>"true", "region_id"=>nil}], ["2", "All"]=>[{"school_id"=>"2", "plan_type"=>"All", "edit"=>"true", "grant"=>"true", "region_id"=>nil}]}

####reduce

reduce作用和inject优点类似，但是它比inject还要简洁

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(5..10).inject {|sum, n| sum + n } # 45 (5..10).reduce(:+) # 45 (5..10).reduce(1, :+) # 46 (括号中第一个参数是初始值，第二个是方法名)

以group_by中的array为例，将相同school_id的hash进行合并

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array.group_by { |e| e["school_id"] }.values.map { |i| i.inject({}) { |sum ,e| sum.merge e }} => [{"school_id"=>"1", "plan_type"=>"All", "view"=>"true", "create"=>"true", "approve"=>"true", "grant"=>"true", "region_id"=>nil, "edit"=>"true"}, {"school_id"=>"2", "plan_type"=>"All", "edit"=>"true", "grant"=>"true", "region_id"=>nil}]

可以使用inject将hash合并，但是使用reduce效果会更好

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array.group_by { |e| e["school_id"] }.values.map { |i| i.reduce(:merge) } => [{"school_id"=>"1", "plan_type"=>"All", "view"=>"true", "create"=>"true", "approve"=>"true", "grant"=>"true", "region_id"=>nil, "edit"=>"true"}, {"school_id"=>"2", "plan_type"=>"All", "edit"=>"true", "grant"=>"true", "region_id"=>nil}]

####zip

zip可以将两个数组合并为一个二维数组

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a= [1,2,3,4,5] b=[6,7,8,9,10] a.zip(b) => [[1, 6], [2, 7], [3, 8], [4, 9], [5, 10]]

如果a.length > b.length，b中缺少的以nil代替 ，

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a=[1,2,3,4,5,6] b=[6,7,8,9,10] a.zip(b) => [[1, 6], [2, 7], [3, 8], [4, 9], [5, 10], [6, nil]]

如果a.length < b.length，b中多余的直接被丢弃

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a= [1,2,3,4] b=[6,7,8,9,10] a.zip(b) => [[1, 6], [2, 7], [3, 8], [4, 9]]

 

 

 

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